Answer:
The frictional force acting on the bear during the slide is 207.5 N
Explanation:
Given;
mass of beam, m = 25-kg
vertical height, h = 12 m
speed of fall, v = 6 m/s
Change in potential energy of the beam:
ΔP.E = -mgh = - 25 x 9.8 x 12 = -2940 J
Change in kinetic energy of the beam:
Δ K.E = ¹/₂mv² = ¹/₂ x 25 x (6)² = 450 J
Change in thermal energy of the system due to friction:
ΔE = - (ΔP.E + Δ K.E)
ΔE = - (-2940 J + 450 J)
ΔE = 2940 J - 450 J = 2490 J
Frictional force (in N) acting on the bear during the slide:
F x d = Fk x h = ΔE
Where;
Fk is the frictional force
Fk = ΔE/h
Fk = 2490J / 12m
Fk = 207.5 N
Therefore, the frictional force acting on the bear during the slide is 207.5 N
Below is an attachment containing the solution.
Answer:
A friction
Explanation:
Friction is the force resisting the relative motion of solid surfaces, fluid layers, and material elements sliding against each other.
Answer:
The minimum number of 100 Ω resistors that i need to design an effective resistor with 275Ω resistance are 8 resistors.
Explanation:
(2 Resistors of 100Ω in parallel) in <u>series with</u> (4 resistors of 100Ω in parallel) in <u>series</u> with 2 resistors of 100Ω.
2 resistors in parallel of 100Ω = 50Ω
+
4 resistors in parallel of 100Ω = 25Ω
+
2 resistors in series of 100 2Ω = 200Ω
=
275Ω
It would be sedimentary rocks