Question

What is the solution to the system: ax+y=18 and 4ax-y=12? Use elimination. Put the answer as an ordered pair. Show work on the next question. You have 3 unknowns and only 2 equations so you can have the variable "a" in your solution

Answer 1

Answer:

{($\frac{6}{a}$,12)}

Step-by-step explanation:

$\left \{ {{ax+y=18} \atop {4ax-y=12}} \right.$

$5ax = 30$

$x = \frac{6}{a}$

$a(\frac{6}{a}) + y = 18$

6 + y =18→y=12

$4a(\frac{6}{a}) - 12 = 12$

6 - 12 = 12 → 12 = 12 true  x=$\frac{6}{a}$  y=12

Answer 2

Answer:

Ax=6

Y=12

Therefore a=6, x=1, y=12