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pav-90 [236]
3 years ago
13

VVVVVVVVVVVVVVVVVVVVVVVVV

Mathematics
1 answer:
defon3 years ago
5 0

Answer:

well i divided the votes he got with the votes u where suppose to get an i got 0.56 i dont really know if its right so like ask someone smarter i tried my best but u can try




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CRITICAL THINKING The total area of the polygon is 176 square feet. What is the value of $x$ ?
Katarina [22]

Answer:

x = 6

Step-by-step explanation:

this figure involves two triangle and one rectangle

for area of rectangle= Length * Width = 16 * 8 = 128 feet^2

for area of one triangle = 1/2 * base * height = 1/2 * x *8 = 4x

for two triangles = 8x ft^2 total

whole area = two triangles + one rectangle

176 = 8x + 128

8x =48

x = 6

8 0
3 years ago
Plz help and plz show work
sammy [17]

Answer:

total miles = miles per day × number of days

M=m×d

8 0
3 years ago
Read 2 more answers
Which ratio would help find the distance the person is from the flag pole ¨X¨ if the angle is elevation of 30 degrees.
WINSTONCH [101]

Answer:

There are three major trignometric ratios in mathematics and they are:

sine(sin), cosine(cos) and tangent(tan). A popular acronym is used in recalling the formula for each ratio and it is: SOH-CAH-TOA.

Sine(x) = Opp/Hyp

Cosine(x) = Adj/Hyp

Tangent(x) = Opp/Adj

Now, the Hyp is the hypothenus of the triangle and it is the side opposite to angle 90. The opposite and adjacent is kind of relative depending on the angle been considered. For this case, we are considering angle 30 which the opposite side is 60 and the remaining side becomes the adjacent

Step-by-step explanation:

tan 30 = 60/x

5 0
3 years ago
Five year old Michelle weighs 75 decagrams. What is her weight in centigrams?
Svet_ta [14]
It should be 75000. I don’t know. I looked this up but I still hope this helps!
3 0
3 years ago
Read 2 more answers
How to find imaginary zeros anf real zeros of F(x)=-4x^5-8x^3+12x​
Fofino [41]

Answer:

x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}

Step-by-step explanation:

We are given the function:

f(x)=-4x^5-8x^3+12x

And we want to finds its zeros.

Therefore:

0=-4x^5-8x^3+12x

Firstly, we can divide everything by -4:

0=x^5+2x^3-3x

Factor out an x:

0=x(x^4+2x^2-3)

This is in quadratic form. For simplicity, we can let:

u=x^2

Then by substitution:

0=x(u^2+2u-3)

Factor:

0=x(u+3)(u-1)

Substitute back:

0=x(x^2+3)(x^2-1)

By the Zero Product Property:

x=0\text{ and } x^2+3=0\text{ and } x^2-1=0

Solving for each case:

x=0\text{ and } x=\pm\sqrt{-3}\text{ and } x=\pm\sqrt{1}

Therefore, our real and complex zeros are:

x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}

4 0
2 years ago
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