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3 years ago

Plss help :((((((((((((

Mathematics

1 answer:

ale4655 [162]3 years ago

8 0

Answer:

The answer is c

i do believe but you never know

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Show your mastery of multiplying fractions by using the sketchpad to find the product of 3-4 x 37

diamong [38]

Answer:

$\frac{111}{4}$

27 $\frac{3}{4}$

Step-by-step explanation:

Any regular whole number (37 for example) is over one so it would look like $\frac{37}{1}$ . Multiplying fractions involve just multiplying the numerators and denominators together, therefore it would look like $\frac{3}{4}$ × $\frac{37}{1}$ . Now just multiply the top and bottom numbers together and this will leave you with $\frac{111}{4}$ . But if you'd like to make it into a mixed number (more simplified version of $\frac{111}{4}$ ) then you would get 27 $\frac{3}{4}$ .

8 0

3 years ago

If 1503 kg of rice was packed in sacks weighing 3 kg each, how many sacks were packed

AURORKA [14]

Answer:

501 sacks

Step-by-step explanation:

please mark me as brainlest

6 0

3 years ago

What is the solution to the inequality 6 − 2x < 4?

slega [8]

X>1 if that helps with your problem

4 0

3 years ago

An executive committee consists of 15 members: 7 men & 8 women. 5 members are selected at random to attend a meeting in Hawa

asambeis [7]

Answer:

1.8%

Step-by-step explanation:

(8c5 * 7c0)/15c5

= 0.018

This is the answer which I get when I solve this... cross check the calculations once.

3 0

3 years ago

A market research team thinks that their new ad campaign is better than their old one. They used to be able to sell to 50% of th

andreev551 [17]

Answer:

a. The test statistic is 2 and we conclude that the new ad campaign is not signficantly better.

Step-by-step explanation:

They used to be able to sell to 50% of those who saw their ads. Test if the new campaign is better.

At the null hypothesis, we test is it is the same, that is, the proportion is the same.

$H_0: p = 0.5$

At the alternate hypothesis, we test if it is significantly better, that is, the proportion is above 50%.

$H_1: p > 0.5$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.5 is tested at the null hypothesis:

This means that $\mu = 0.5, \sigma = \sqrt{0.5*0.5} = 0.5$

They take a random sample of 100 potential buyers and find that they convinced 60 of these people to buy their product.

This means that $n = 100, X = \frac{60}{100} = 0.6$

Test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.6 - 0.5}{\frac{0.5}{\sqrt{100}}}$

$z = 2$

The test statistic is 2.

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion above 0.6, which is 1 subtracted the by p-value of z = 2.

Looking at the z-table, z = 2 has a p-value of 0.9772.

1 - 0.9772 = 0.0228.

The p-value of the test is 0.0228 > 0.01, which means that we cannot conclude that the new ad campaign is signficantly better, so the correct answer is given by option A.

5 0

3 years ago