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viktelen [127]
3 years ago
11

Anybody know how to answer this? Explain if you can, please :)

Mathematics
1 answer:
garik1379 [7]3 years ago
5 0
Carrie is 2 and Kim is just born.
you can have,

Carrie = 3      4     5     6
    Kim = 1      2     3     4

Or something like that, thats a table btw

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Amy Miller’s insurance policy includes 25/100 bodily injury limits and $25,000 property damage. Her vehicle is in age group B an
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For each problem, find the missing value using the Pythagorean Theorem
aniked [119]

Answer: \sqrt{66}

Step-by-step explanation:

The Pythagorean Theorem says that a^2 + b^2 = c^2  where a and b are the two legs.  

In this care leg 1 is 4 and leg two is the square root of 50. So we will square them to find c which is the hypotenuse.

4^2 + \sqrt{50} ^2  = C^2

16 +  50 = c^2

  66 = c^2

    c =\sqrt{66}  

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3 years ago
This Assignment will be used as a QUIZ GRADE!
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2 years ago
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Math help is needed ps how is your day going ?
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Step-by-step explanation:

nothing much

3 0
3 years ago
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Assume that we have two events, and , that are mutually exclusive. Assume further that we know and . If an amount is zero, enter
sweet [91]

Answer:

Explained below.

Step-by-step explanation:

The complete question is:

Assume that we have two events, A and B, that are mutually exclusive. Assume further that we know P(A) = 0.30 and P(B) =0.40.

What is P(A and B)?

What is P(A | B)?

Is P(A | B) equal to P(A)?

Are events A and B dependent or independent?

A student in statistics argues that the concepts of mutually exclusive events and independent events are really the same, and that if events are mutually exclusive they must be independent. Is this statement accurate?

What general conclusion would you make about mutually exclusive and independent events given the results of this problem?

Solution:

The probability of the two events <em>A</em> and <em>B</em> are:

P(A) = 0.30 and P(B) =0.40

(a)

Compute the value of P (A ∩ B) as follows:

P(A\cap B)=0

This is because mutually exclusive events are those events that cannot occur together.

(b)

Compute the value of P (A | B) as follows:

P(A|B)=\frac{P(A\cap B)}{P(B)}=\frac{0}{0.40}=0

Thus, the value of P (A | B) is 0.

(c)

No, P (A | B) is not equal to the P (A).

(d)

As mentioned in part (a), mutually exclusive events are those events which cannot occur together.

That is, P(A\cap B)=0.

Events A and B are independent  if the chance of their concurrent happening is equivalent to the multiplication of their distinct probabilities.

That is, P(A\cap B)=P(A)\times P(B).

The concepts of mutually exclusive events and independent events are not the same.

(e)

As the it is provided that A and B are mutually exclusive events, we know that P(A\cap B)=0.

Now compute the value of P(A)\times P(B) as follows:

               P(A)\times P(B)=0.30\times 0.40=0.12\neq 0

Thus, the events A and B are not independent.

Thus, if two events are mutually exclusive events they cannot be independent.

4 0
3 years ago
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