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bekas [8.4K]
3 years ago
11

Can someone help me out?

Mathematics
1 answer:
olasank [31]3 years ago
8 0

Answer:

Slope is positive.

Every additional hat produced results in a cost increase of $0.60

Before producing any hats the cost is about $100

Step-by-step explanation:

Calculate the slope or rate of change using two data points from the table.

m = \frac{111-105}{20-10} =\frac{6}{10}

This means that the cost rises by $6 for every 10 hats or 0.60 per 1 hat. The slope is positive and increasing.

This also means that for 0 hats the cost is 105-6 = 99 or about $100.

You might be interested in
A total of 243 tickets were sold for the school play. They were either adult tickets or student tickets. The number of student t
alina1380 [7]

Answer:

81 adult tickets

Step-by-step explanation:

Step 1:

Set up a system of equations

Since the adult tickets and student tickets add to 243, we can do

a+s=243

and the student tickets sold were 2x the adult tickets, we can do

s=2a

We can replace s in the first equation adding to 243 with 2a

a+s(2a)=243\\3a=243\\

Step 2:

Solve for a. We can divide both sides by 3.

a=81

Therefore, there were 81 adult tickets sold.

Step 3:

We can check our work! Since we learned earlier the student tickets are 2x adult tickets, we can multiply 81 by 2 and add that to 81 to see if it equals 243!

s=2a\\s=2(81)\\s=162

And...

162+81=243

So, 81 must be the answer!

8 0
2 years ago
Read 2 more answers
Emery bought 3 cans of beans that had a total weight of 2.4 pounds. If each can of beans weighed the same amount, which model co
andreev551 [17]

Answer:

  • y=0.8x
  • See Explanation for others

Step-by-step explanation:

The 3 cans of beans had a total weight of 2.4 Pounds

Therefore:

  • 1 can of beans = (2.4 ÷ 3) =0.8 Pounds

The following applies from the options.

  • y=0.8x where y is the weight and x is the number of cans.
  • A 2-column table with 3 rows. Column 1 is labeled number of cans with entries 5, 15, 20. Column 2 is labeled total weight (in pounds) with entries 4, 12, 16.

Using y=0.8x

When x=5, y=0.8 X 5=4

When x=15, y=0.8 X 15=12

When x=20, y=0.8 X 20=16

\left|\begin{array}{c|c}\text{Number of Cans,x}&\text{Total Weight (in Pounds),y}\\-------&--------\\5&4\\15&12\\20&16\end{array}\right|

  • On a coordinate plane, the x-axis is labeled number of cans and the y-axis is labeled total weight (in pounds. A line goes through points (5, 4) and (15, 12). This can be clearly seen from the table above as (5,4) and (15,12) are points on the line.
8 0
3 years ago
Read 2 more answers
Please help me solve this problem
Irina18 [472]

DF is half of AC, so DF=25

7 0
3 years ago
The distribution of lifetimes of a particular brand of car tires has a mean of 51,200 miles and a standard deviation of 8,200 mi
Orlov [11]

Answer:

a) 0.277 = 27.7% probability that a randomly selected tyre lasts between 55,000 and 65,000 miles.

b) 0.348 = 34.8% probability that a randomly selected tyre lasts less than 48,000 miles.

c) 0.892 = 89.2% probability that a randomly selected tyre lasts at least 41,000 miles.

d) 0.778 = 77.8% probability that a randomly selected tyre has a lifetime that is within 10,000 miles of the mean

Step-by-step explanation:

Problems of normally distributed distributions are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 51200, \sigma = 8200

Probabilities:

A) Between 55,000 and 65,000 miles

This is the pvalue of Z when X = 65000 subtracted by the pvalue of Z when X = 55000. So

X = 65000

Z = \frac{X - \mu}{\sigma}

Z = \frac{65000 - 51200}{8200}

Z = 1.68

Z = 1.68 has a pvalue of 0.954

X = 55000

Z = \frac{X - \mu}{\sigma}

Z = \frac{55000 - 51200}{8200}

Z = 0.46

Z = 0.46 has a pvalue of 0.677

0.954 - 0.677 = 0.277

0.277 = 27.7% probability that a randomly selected tyre lasts between 55,000 and 65,000 miles.

B) Less than 48,000 miles

This is the pvalue of Z when X = 48000. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{48000 - 51200}{8200}

Z = -0.39

Z = -0.39 has a pvalue of 0.348

0.348 = 34.8% probability that a randomly selected tyre lasts less than 48,000 miles.

C) At least 41,000 miles

This is 1 subtracted by the pvalue of Z when X = 41,000. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{41000 - 51200}{8200}

Z = -1.24

Z = -1.24 has a pvalue of 0.108

1 - 0.108 = 0.892

0.892 = 89.2% probability that a randomly selected tyre lasts at least 41,000 miles.

D) A lifetime that is within 10,000 miles of the mean

This is the pvalue of Z when X = 51200 + 10000 = 61200 subtracted by the pvalue of Z when X = 51200 - 10000 = 412000. So

X = 61200

Z = \frac{X - \mu}{\sigma}

Z = \frac{61200 - 51200}{8200}

Z = 1.22

Z = 1.22 has a pvalue of 0.889

X = 41200

Z = \frac{X - \mu}{\sigma}

Z = \frac{41200 - 51200}{8200}

Z = -1.22

Z = -1.22 has a pvalue of 0.111

0.889 - 0.111 = 0.778

0.778 = 77.8% probability that a randomly selected tyre has a lifetime that is within 10,000 miles of the mean

4 0
2 years ago
Ahmad Conan deposited 60 quarters, 53 dimes, 44 nickels, and 50 pennies into his checking account. The total of the checks he de
Galina-37 [17]

Answer:

40 $

Step-by-step explanation:

He first deposited 60 quarters=15$, 53 dimes=5.3$, 44 nickels=2.2$, and 50 pennies=0.5$ Total 23$

23$+17$=2*(total deposit)

so total deposit = 20

"If Ahmad received 2 twenty-dollar bills in cash" - does not mean that he deposited those 40$

so total deposit = 20$

4 0
2 years ago
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