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JulsSmile [24]
3 years ago
8

PLEASE HELP ME I WILL GIVE YOU SO MANY BRAINLY POINTS!!!!!!!!!!!!!!

Mathematics
1 answer:
MrRa [10]3 years ago
3 0
D or the last one
That the point (72,34) is apart of the solution.
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Sean says that to add a number to -100 and still have -100 is to add a zero.Candice says that she can add 2 numbers to -100 and
vekshin1

Answer:

Sean because zero added to anything is the same answer.

Step-by-step explanation:

6 0
4 years ago
Howard's pawn shop bought an antique clock at the wholesale price of $725. Howard marked up the price of the clock
kkurt [141]

Answer:

942.50

Step-by-step explanation:

725×30% or 0.3 = 217.5

217.5+725=942.5

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3 years ago
Select the expressions that are equivalent to 8 2/3
user100 [1]
To change a mixed fraction, you'd multiply the number upfront, times the denominator, and then add that product to the numerator
that IS the new numerator, and you keep the denominator
thus \bf 8\frac{2}{3}\iff \cfrac{8\cdot 3+2}{3}
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3 years ago
Need help asap !!!!!
Mandarinka [93]
The answer should be 61
4 0
3 years ago
Read 2 more answers
5) Two machines M1, M2 are used to manufacture resistors with a design
Basile [38]

Answer:

Since M1 has the higher probability of being in the desired range, we choose M1.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Two machines M1, M2 are used to manufacture resistors with a design specification of 1000 ohm with 10% tolerance.

So we need the machines to be within 1000 - 0.1*1000 = 900 ohms and 1000 + 0.1*1000 = 1100 ohms.

For each machine, we need to find the probabilty of the machine being in this range. We choose the one with the higher probability.

M1:

Resistors of M1 are found to follow normal distribution with mean 1050 ohm and standard deviation of 100 ohm. This means that \mu = 1050, \sigma = 100

The probability is the pvalue of Z when X = 1100 subtracted by the pvalue of Z when X = 900. So

X = 1100

Z = \frac{X - \mu}{\sigma}

Z = \frac{1100 - 1050}{100}

Z = 0.5

Z = 0.5 has a pvalue of 0.6915.

X = 900

Z = \frac{X - \mu}{\sigma}

Z = \frac{900 - 1050}{100}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.6915 - 0.0668 = 0.6247.

M1 has a 62.47% probability of being in the desired range.

M2:

M2 are found to follow normal distribution with mean 1000 ohm and standard deviation of 120 ohm. This means that \mu = 1000, \sigma = 120

X = 1100

Z = \frac{X - \mu}{\sigma}

Z = \frac{1100 - 1000}{120}

Z = 0.83

Z = 0.83 has a pvalue of 0.7967.

X = 900

Z = \frac{X - \mu}{\sigma}

Z = \frac{900 - 1000}{120}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033

0.7967 - 0.2033 = 0.5934

M2 has a 59.34% probability of being in the desired range.

Since M1 has the higher probability of being in the desired range, we choose M1.

8 0
3 years ago
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