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strojnjashka [21]
3 years ago
10

3 x 3 + 3^2-6 pemdas

Mathematics
2 answers:
marusya05 [52]3 years ago
8 0

Answer:this site will help you with all you math , history and all subjets. good luke.

Step-by-step explanation:

https://www.khanacademy.org/math/pre-algebra/pre-algebra-arith-prop/pre-algebra-order-of-operations/v/more-complicated-order-of-operations-example

liubo4ka [24]3 years ago
5 0

Answer:

12

Step-by-step explanation:

Following the order of operations.

Evaluate exponents and multiplication before adding/ subtracting

Given

3 × 3 + 3² - 6 ← evaluate the exponent

= 3 × 3 + 9 - 6 ← evaluate multiplication

= 9 + 9 - 6 ← evaluate from left to right

= 18 - 6

= 12

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Laura painted her room with pink paint that was made by mixing paint at a ratio of 5 parts white paint to 2 parts red paint. Wil
lakkis [162]

Answer:

No

Step-by-step explanation:

Laura painted her room with pink paint that was made by mixing paint at a ratio of 5 parts white paint to 2 parts red paint.

Suppose Laura has 15 parts of white paint. This is thrice the amount Laura needs (because 15:5=3), so she has to have

2\cdot 3=6

parts of red paint.

Hence, if Laura combines 15 parts white and 3 parts red paint, then she will not create the same shade of pink as she used.

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3 years ago
Does the alligator eat 14/7 or 2/4
klasskru [66]
They eat when they hungry LOL
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3 years ago
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A textbook costs $65.49 before tax. The tax on the textbook is 6.5%. What is the total cost of the textbook? Round your answer t
Ghella [55]

Answer: $69.75.


Step-by-step explanation:

Given: Cost of textbook before tax=$65.49

The tax on the textbook = 6.5%

∴ The tax amount = 6.5% of $65.49

=\frac{65}{1000}\times65.49=4.25685\approx4.26

⇒The tax amount = $4.26

The total cost of the textbook=Cost of textbook before tax+tax amount

=$65.49+$4.26

=$69.75

∴ The total cost of the textbook is $69.75.

3 0
3 years ago
Which is a diagonal through the interior of the cube?
Wittaler [7]

Answer:

FG i think

Step-by-step explanation:

3 0
3 years ago
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5.2.14. For the negative binomial pdf p (k; p, r) = k+r−1 (1 − p)kpr, find the maximum likelihood k estimator for p if r is know
Volgvan

Answer:

\hat p = \frac{r}{\bar x +r}

Step-by-step explanation:

A negative binomial random variable "is the number X of repeated trials to produce r successes in a negative binomial experiment. The probability distribution of a negative binomial random variable is called a negative binomial distribution, this distribution is known as the Pascal distribution".

And the probability mass function is given by:

P(X=x) = (x+r-1 C k)p^r (1-p)^{x}

Where r represent the number successes after the k failures and p is the probability of a success on any given trial.

Solution to the problem

For this case the likehoof function is given by:

L(\theta , x_i) = \prod_{i=1}^n f(\theta ,x_i)

If we replace the mass function we got:

L(p, x_i) = \prod_{i=1}^n (x_i +r-1 C k) p^r (1-p)^{x_i}

When we take the derivate of the likehood function we got:

l(p,x_i) = \sum_{i=1}^n [log (x_i +r-1 C k) + r log(p) + x_i log(1-p)]

And in order to estimate the likehood estimator for p we need to take the derivate from the last expression and we got:

\frac{dl(p,x_i)}{dp} = \sum_{i=1}^n \frac{r}{p} -\frac{x_i}{1-p}

And we can separete the sum and we got:

\frac{dl(p,x_i)}{dp} = \sum_{i=1}^n \frac{r}{p} -\sum_{i=1}^n \frac{x_i}{1-p}

Now we need to find the critical point setting equal to zero this derivate and we got:

\frac{dl(p,x_i)}{dp} = \sum_{i=1}^n \frac{r}{p} -\sum_{i=1}^n \frac{x_i}{1-p}=0

\sum_{i=1}^n \frac{r}{p} =\sum_{i=1}^n \frac{x_i}{1-p}

For the left and right part of the expression we just have this using the properties for a sum and taking in count that p is a fixed value:

\frac{nr}{p}= \frac{\sum_{i=1}^n x_i}{1-p}

Now we need to solve the value of \hat p from the last equation like this:

nr(1-p) = p \sum_{i=1}^n x_i

nr -nrp =p \sum_{i=1}^n x_i

p \sum_{i=1}^n x_i +nrp = nr

p[\sum_{i=1}^n x_i +nr]= nr

And if we solve for \hat p we got:

\hat p = \frac{nr}{\sum_{i=1}^n x_i +nr}

And if we divide numerator and denominator by n we got:

\hat p = \frac{r}{\bar x +r}

Since \bar x = \frac{\sum_{i=1}^n x_i}{n}

4 0
3 years ago
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