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2 years ago

Identify the slope and y-intercept of the function y=11x+6

2 answers:

8 0

The slope-intercept form is y=mx+b y = m x + b , where m is the slope and b is the y-intercept. Find the values of m and b using the form y=mx+b y = m x + b . The slope of the line is the value of m , and the y-intercept is the value of b .

Step-by-step explanation:

Leviafan [203]2 years ago

8 0

Answer:

let me see what i can do

Step-by-step explanation:

isolate the variable by dividing each side by factors that don´t contain the variable x = - 4/11 + 6/11

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Rewrite expression as a single power<img src="https://tex.z-dn.net/?f=6%5E%7B4%7D%2A%206%5E%7B4%7D" id="TexFormula1" title="6^{4

victus00 [196]

Answer:

6^8

Step-by-step explanation:

6^4 * 6^4

We know that a^b * a^c = a^( b+c)

6^(4+4)

6^8

5 0

3 years ago

Read 2 more answers

The graph of the continuous function g, the derivative of the function f, is shown above. The function g is piecewise linear for

4vir4ik [10]

A) $g=f'$ is continuous, so $f$ is also continuous. This means if we were to integrate $g$ , the same constant of integration would apply across its entire domain. Over $0$ , we have $g(x)=2x$ . This means that

$f_{0$

For $f$ to be continuous, we need the limit as $x\to1^-$ to match $f(1)=3$ . This means we must have

$\displaystyle\lim_{x\to1}x^2+C=1+C=3\implies C=2$

Now, over $x$ , we have $g(x)=-3$ , so $f_{x$ , which means $f(-5)=17$ .

b) Integrating over [1, 3] is easy; it's just the area of a 2x2 square. So,

$\displaystyle\int_1^6g(x)=4+\int_3^62(x-4)^2\,\mathrm dx=4+6=10$

c) $f$ is increasing when $f'=g>0$ , and concave upward when $f''=g'>0$ , i.e. when $g$ is also increasing.

We have $g>0$ over the intervals $0$ and $x>4$ . We can additionally see that $g'>0$ only on $0$ and $x>4$ .

d) Inflection points occur when $f''=g'=0$ , and at such a point, to either side the sign of the second derivative $f''=g'$ changes. We see this happening at $x=4$ , for which $g'=0$ , and to the left of $x=4$ we have $g$ decreasing, then increasing along the other side.

We also have $g'=0$ along the interval $-1$ , but even if we were to allow an entire interval as a "site of inflection", we can see that $g'>0$ to either side, so concavity would not change.

5 0

3 years ago

Angles α and β are the two acute angles in a right triangle. Use the relationship between sine and cosine to find the value of β

Dimas [21]

Answer:

From given relation the value of β is 37.5°

Step-by-step explanation:

Given as :

α and β are two acute angles of right triangle

Acute angle have measure less than 90°

Now given as :

$sin(\frac{x}{2} + 2x)$ = $cos(2x +\frac{3x}{2})$