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4 years ago

Can someone please help me this? Math 8

Mathematics

1 answer:

Viefleur [7K]4 years ago

5 0

Answer:

$5x + ( - 8)x + 9 + ( - 4) \\ 5x - 8x + 9 - 4 \\ - 3x + 5$

this is the solution

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Need help now!! 20 points!!

Gelneren [198K]

When you have something like this, all you need to do is substitute the values, the last is for what value of x

For the first one;

((x^2+1)+(x-2))(2)

(x^2+x-1)(2)

(2)^2+(2)-1

4+2-1

For the second one;

((x^2+1)-(x-2))(3)

(x^2-x+3)(3)

(3)^2-(3)+3

9-3+3

For the last one;

3(x^2+1)(7)+2(x-2)(3)

3((7)^2+7)+2((3)-2)

3(49+7)+2(3-2)

3(56)+2(1)

168+2

170

3 0

3 years ago

(-2)2+3 × (-5) <br> please helpe me answer this question

Tpy6a [65]

Answer:

(−2)(2)+(3)(−5)

=−19

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Add: -5g^2+(-9g^2-8)

Amiraneli [1.4K]

Answer:

$\boxed{-14g^2 - 8}$

Step-by-step explanation:

$-5g^2 + (-9g^2 - 8)$

$= - 5g^2 - 9g^2 - 8$

$= -14g^2 - 8$

3 0

3 years ago

Y 65° 25 <br>can someone solve this ?

n200080 [17]

Answer: a=25

Explanation: I am assuming you are looking for “a” so if you heard the method of 45, 45, 90 it helps you solve it. So by the 45 being across from 25 makes the 45 across a 25 as well, hope this was what you were looking for…

7 0

3 years ago

The heights (in inches) and pulse rates (in beats per minute) for a sample of 40 women were measured. Using technology with the

Viktor [21]

Answer:

There is not sufficient evidence to support the claim that there is a linear correlation between the heights and pulse rates of women

Step-by-step explanation:

The correlation coefficient between the variables h(height in inches) and pulse rates (in beats per minute) is 0.202

Sample size n=40

Level of significane alpha = 0.01

Create null and alternate hypothesis as:

H0: r=0

Ha: r not equal 0

(Two tailed test at 1% significance level)

Sample r = 0.202

r difference = 0.202

test statistic t = $\frac{r\sqrt{n-2} }{\sqrt{1-r^2} } \\=\frac{0.202(\sqrt{38} )}{\sqrt{0.9592} } \\=\frac{1.25}{0.9794} \\=1.271$

df =n-2 =38

t critical value for 0.01 and df =38 is 2.704

Since our test statistic lies below 2.704, we accept null hypothesis

There is not sufficient evidence to support the claim that there is a linear correlation between the heights and pulse rates of women

7 0

4 years ago