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bazaltina [42]
3 years ago
7

Hamburger heaven is having a lunch special where customers buy one 3/4 pounds cheese burger and get one free if they set aside 1

06 2/3 pounds of meat how many 3/4 pounds chessburgers can they make
Mathematics
1 answer:
Yuri [45]3 years ago
5 0

Answer:

49

Step-by-step explanation:

49 hamburguers (of 3/4 pound)

Step-by-step explanation:

3/4 pound is equal to 0.75 pound

37 1/3 pounds of meat is equal to

37 + 1/3 pound =  37.3333 pounds

To find how much hamburguers can be made, we need to divide

37.3333 pounds/ 0.75 pounds

37.3333 pounds/ 0.75 pounds = 49.777777

(We need to round to the lowest number)

This means that 49 hamburguers could be made

Plz mark brainliest

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Distance = 585 x 1/600 = 585/600 = 0.975 miles

Convert miles to feet:

0.975 x 5280 = 5,148 feet

The plane traveled 5,148 feet in 6 seconds.

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3 years ago
Can y’all help me on question 40?!
miss Akunina [59]

Answer:

Step-by-step explanation:

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A farmer has enough food to feed 20 animals in his cattle for 6 days. How long would the food last if there were 10 more animals
andrew11 [14]

Answer:

A farmer has enough food to feed 20 animals in his cattle for 6 days. How long would the food last if there were 10 more animals in his cattle? Here the number of animals and the number of days are in inverse proportion. Hence the food will last 4 days.

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3 years ago
determine the point of intersection of the following pair of lines ............2x-3y-4=-13 and 5x=-2y+25. 3x+2y-7=0 and 2x=12-5y
grandymaker [24]

Answer:

  1. (x, y) = (3, 5)
  2. (x, y) = (1, 2)

Step-by-step explanation:

A nice graphing calculator app makes these trivially simple. (See the first two attachments.) It is available for phones, tablets, and as a web page.

__

The usual methods of solving a system of equations involve <em>elimination</em> or <em>substitution</em>.

There is another method that is relatively easy to use. It is a variation of "Cramer's Rule" and is fully equivalent to <em>elimination</em>. It makes use of a formula applied to the equation coefficients. The pattern of coefficients in the formula, and the formula itself are shown in the third attachment. I like this when the coefficient numbers are "too messy" for elimination or substitution to be used easily. It makes use of the equations in standard form.

_____

1. In standard form, your equations are ...

  • 2x -3y = -9
  • 5x +2y = 25

Then the solution is ...

  x=\dfrac{-3(25)-(2)(-9)}{-3(5)-(2)(2)}=\dfrac{-57}{-19}=3\\\\y=\dfrac{-9(5)-(25)(2)}{-19}=\dfrac{-95}{-19}=5\\\\(x,y)=(3,5)

__

2. In standard form, your equations are ...

  • 3x +2y = 7
  • 2x +5y = 12

Then the solution is ...

  x=\dfrac{2(12)-5(7)}{2(2)-5(3)}=\dfrac{-11}{-11}=1\\\\y=\dfrac{7(2)-12(3)}{-11}=\dfrac{-22}{-11}=2\\\\(x,y)=(1,2)

_____

<em>Note on Cramer's Rule</em>

The equation you will see for Cramer's Rule applied to a system of 2 equations in 2 unknowns will have the terms in numerator and denominator swapped: ec-bf, for example, instead of bf-ec. This effectively multiplies both numerator and denominator by -1, so has no effect on the result.

The reason for writing the formula in the fashion shown here is that it makes the pattern of multiplications and subtractions easier to remember. Often, you can do the math in your head. This is the method taught by "Vedic maths" and/or "Singapore math." Those teaching methods tend to place more emphasis on mental arithmetic than we do in the US.

7 0
3 years ago
Is table A liner or nonlinear
Kipish [7]
I think table A is liner
7 0
3 years ago
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