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GaryK [48]
3 years ago
8

I need help only on number 3

Mathematics
1 answer:
DochEvi [55]3 years ago
8 0
Gaps have no data in them. So the range 1-2 is a gap.

Clusters are groups of data that are right next to each other.

So the range 3-6 on your dot plot is a cluster, because there is a group of data there with no gaps.

Peaks are the greatest amount of data in the dot plot. 0 and 5 are the peaks because they both have the most data, 4.

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Answer:

Step-by-step explanation:

P=5/12×2/12=5/72

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What is 3 pi plus 2 pi over 3?
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11 pi over 3

Step-by-step explanation:

you have to convert 3 pi into a fraction and add that to 2 pi over 3. Since the denominators are equal, you have to combine the fractions which would equal 11 pi over 3, if that makes any since

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Someone please assist more especially number 8,9 and 10
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Solve 2x+x-3 will mark brainliest
Alexus [3.1K]

Answer:

3x−3

Step-by-step explanation:

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Use matrices to determine the coordinates of the vertices of the reflected figure. Then graph the pre-image and the image on the
Troyanec [42]

Answer:

The coordinates of the vertices of the reflected figure are :

R' is (5 , -2) , S' is (3 , 5) , T' is (-7 , 6) ⇒ the right answer is (d)

Step-by-step explanation:

* When you reflect a point across the line y = x, the x-coordinate

 and y-coordinate change their places.

- If the point is (x , y) then its image is (y , x)

* If you reflect over the line y = -x, the x-coordinate and y-coordinate

 change their places and their signs

- If the point is (x , y) then its image is (-y , -x)

* Lets study the matrix of the reflection  about the line y = x

- The matrix of the reflection about the line y = x is

 \left[\begin{array}{cc}0&1\\1&0\end{array}\right]

- Because the x-coordinate and y-coordinate change places.

* Now lets solve the problem

- We will multiply the matrix of the reflection about y = x

 by each point to find the image of each point

- The dimension of the matrix of the reflection about y = x

 is 2×2 and the dimension of the matrix of each point is 2×1,

 then the dimension of the matrix of each image is 2×1

∵ The point R is (-2 , 5)

∴ R'=\left[\begin{array}{cc}0&1\\1&0\end{array}\right]\left[\begin{array}{cc}-2\\5\end{array}\right]=

  \left[\begin{array}{c}(0)(-2)+(1)(5)\\(1)(-2)+(0)(5)\end{array}\right]=\left[\begin{array}{c}5\\-2\end{array}\right]

∴ R' is (5 , -2)

∵ The point S is (5 , 3)

∴ S'=\left[\begin{array}{cc}0&1\\1&0\end{array}\right]\left[\begin{array}{c}5\\3\end{array}\right]=

  \left[\begin{array}{c}(0)(5)+(1)(3)\\(1)(5)+(0)(3)\end{array}\right]=\left[\begin{array}{c}3\\5\end{array}\right]

∴ S' is (3 , 5)

∵ The point T is (6 , -7)

∴ T'=\left[\begin{array}{cc}0&1\\1&0\end{array}\right]\left[\begin{array}{c}6\\-7\end{array}\right]=

  \left[\begin{array}{c}(0)(6)+(1)(-7)\\(1)(6)+(0)(-7)\end{array}\right]=\left[\begin{array}{c}-7\\6\end{array}\right]

∴ T' is (-7 , 6)

* Lets look to the figures to find the right answer

∵ The R' is (5 , -2) , S' is (3 , 5) , T' is (-7 , 6)

∴ The right answer is (d)

4 0
3 years ago
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