According to the image, it can be inferred that the economic development of that place did not take into account natural erosion (option A).

<h3>What is natural erosion?</h3>

Erosion is a term that refers to the wear of soil and rocks as a result of different physical and chemical processes on the Earth's surface. In general, erosion implies movement, transport of material, in contrast to the alteration and disintegration of rocks or soil.

According to the above, it can be inferred that the construction of the image did not take into account the erosion of the place because it shows that the foundations of the house are on the land surface that is towards the beach.

From the above, it can be inferred that erosion will degrade the soil in this area as a result of the impact of the waves and the constant wind. This puts the structure at risk because it will lose support and may collapse.

Learn more about erosion in: brainly.com/question/3852201

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8 0

2 years ago

If you were planning to spend a year living abroad, where would you need to pack the greatest range of clothes (for hot and cool

Jlenok [28]

Answer:

Northwestern Eurasia

Explanation:

Geographically the northwestern part of the Eurasia consists of the Ireland, the United Kingdom, Belgium, the Netherlands, Northern Germany, Luxembourg, the Northern France, and the Denmark, and the Norway, the Sweden and the Iceland.

Finland, Southern Germany, the Switzerland these are all the countries that are located near the arctic circle and thus have a cool and cold climate and some are characterized by the oceanic climate type and thus one needs to have thick cloths in order to spend entire year.

4 0

4 years ago

A 215 kg rocket moving radially outward from Earth has a speed of 6.42 km/s when its engine shuts off 307 km above Earth's surfa

Vinvika [58]

<h2>GIVEN DATA</h2>

Mass of Rocket = m = 215 kg

Mass of Earth = M = $5.97*10^{24}$ kg

Radius of Earth = R = $6.37*10^6$ m

Gravitational Constant = G = $6.67*10^-11 \;\;m^3kg^{-1}s^{-2}$

Speed of Rocket = 6.42 km/s

Initial Height of Rocket from Earth's Surface = 307 km = $3.07*10^5$ m

Final Height of Rocket from Earth's Surface = 731 km = $7.31*10^5$ m

Initial Height from Earth's Centre = $R_i$ = $3.07*10^5 + 6.37*10^6 = 6.677*10^6$ m

Final Height from Earth's Surface = $R_f$ = $7.31*10^5 + 6.37*10^6 = 7.101*10^6$ m

(a) Kinetic Energy at Final Height = $K.E_f$

(b) Maximum Height of Rocket above Earth's Surface = $H_{max}$

<h2>EXPLANATION</h2>

Part (a):

As drag air is negligible, energy will be conserved.

$\therefore$ ΔE = 0

$K.E_i + U_i = K.E_f + U_f$

$K.E_f = U_f - K.E_i - U_i$

where, U is the potential energy of the system.

$K.E_f=\;G\frac{mM}{R_f} + \frac{1}{2}mv_i^2\;-\;G\frac{mM}{R_i}\;\;\;\;----------\;(1)$

Substituting Values and simplifying,

$K.E_f = 3.665*10^9 J$

Part (b):

The rocket will come to rest after reaching the maximum height. Therefore, its final velocity and consequently final kinetic energy will be zero.

$i.e.\;\;v_f = 0\;\;\;\&\;\;\; K.E_f=0$

Equation (1) will become,

$0\;=\;\;G\frac{mM}{R_f} + \frac{1}{2}mv_i^2\;-\;G\frac{mM}{R_i}$

$or\;\;\frac{1}{2}v_i^2= GM(\frac{1}{R_i}-\frac{1}{R_f})\\\\\frac{1}{2GM}v_i^2= (\frac{1}{R_i}-\frac{1}{R_f})\\\\\therefore\; R_f = \frac{2GMR_i}{2GM-v_i^2R_i}$

Substituting values and simplifying,

$R_f = 10.20*10^6 m$

which is the distance from the Earth's centre. To find the height of rocket from Earth's surface, we simply subtract the Earth's radius from above result.

$H_{max} = R_f - R$

$H_{max} = 10.20*10^6\;-\;6.37*10^6\\\\H_{max} = 3.83*10^6\;\;m$

4 0

3 years ago

A Sample Of A Material has a mass of 185 grams and a volume of 116 cm square.What is the Materials Density?Use the table to Iden

Ray Of Light [21]

Answer:

cdhhjio us goes woods EPA ethics RIA shi usp

6 0

3 years ago

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