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gladu [14]
3 years ago
13

In a class of 7 there are 2 students who forgot their lunch. If the teacher chooses 2 students what is the probability that both

of them forgot their lunch
Mathematics
1 answer:
Reika [66]3 years ago
4 0
It is about a 28% chance.
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What’s the size of angle x
ki77a [65]

Answer:

65 degrees.

Step-by-step explanation:

It's hard to explain, but I'll try:

The outside of the first two angles is 105 and 140. Half a whole angle is 180. So, you do

180-140=40. The inside is 40.

And then 180-105=75.

Then you add the two and subtract them from 180:

40+75= 115

180-115=65

Voila!

7 0
3 years ago
What is the answer to the equation 5+2(x-1)=12
S_A_V [24]
5+2(x-1)=12 \\ \\ 2 ( x - 1) = 12 - 5 \ / \ subtract \ 5 \ from \ each \ side \\ \\ 2(x - 1) = 7 \ / \ simplify \\ \\ x - 1 =  \frac{7}{2} \ / \ divide \ each \ side \ by \ 2 \\ \\ x =  \frac{7}{2}  + 1 \ / \ add \ 1 \ to \ each \ side \\ \\ x =  \frac{9}{2} \ / \ simplify \\ \\

So, the answer to this problem is x = 9/2 or x = 4.5.
3 0
3 years ago
Read 2 more answers
In a group of 10 ​kittens, 5 are female. Two kittens are chosen at random. ​a) Create a probability model for the number of male
olya-2409 [2.1K]

Answer:

(b) Expected number of male kitten E(x) = 1

(c) Standard deviation is ±\frac{2}{3}.

Step-by-step explanation:

Given that,

Number of kittens in a group are 10. Out of these 5 are female.

To find:- (a) create a probability model of male kitten chosen.

    So,  total number of kitten = 10

           number of female kitten = 5    

then, Number of male kitten = 10-5= 5

Now total number of ways to choosing two kittens from group of 10 = ^{10} C_{2}

                                                                                                                 = \frac{10!}{2!\times8!}

                                                                                                                 = 45

for choosing (i) No male P(x=0) = P(Two female) =  \frac{^{5} C_{2}}{45}

                                                                           = \frac{2}{9}

                     (ii) 1 male P(x=1) = P(1 male and 1 female) = \frac{^{5} C_{1}\times^{5} C_{1}}{45} =  \frac{25}{45} =\frac{5}{9}

                     (iii) 2 male P(x=2)= P(2 male) =\frac{^{5} C_{2}}{45} =  \frac{2}{9}

      x_{i}                             0                     1                      2

P(X=x_{i})                           \frac{2}{9}                      \frac{5}{9}                      \frac{2}{9}

(b) what is expected number of male kittens chosen ?

    Expected number of male kitten E(x) =  o\times \frac{2}{9} + 1\times \frac{5}{9} + 2\times\frac{2}{9}

                                                                  = 1

(c) what is standard deviation ?

                              \sigma(x) = \sqrt{ (E(x^{2} )-(Ex)^{2})

No,                          

                               Ex^{2} =o\times \frac{2}{9} + 1\times \frac{5}{9} + 4\times\frac{2}{9}

                                       = \frac{13}{9}

                               \sigma(x)=\sqrt{\frac{13}{9} - 1 }=\sqrt{\frac{4}{9} }  

                                       = ± \frac{2}{3}

                               

6 0
3 years ago
Please help with the graph
tamaranim1 [39]
This is the answers

5 0
3 years ago
Read 2 more answers
3) through: (-1,1), slope = 2
aniked [119]
??? What does that mean
4 0
3 years ago
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