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algol13
1 year ago
13

What is the slope intercept form for x+3y=0

Mathematics
1 answer:
Norma-Jean [14]1 year ago
3 0

Answer:

y = -1/3 x

Step-by-step explanation:

what is the slope intercept form for x+3y=0

Slope intercept form solves for y:

x + 3y = 0

subtract x from both sides:

x + 3y - x = 0 - x

3y = -x

divide both sides by 3:

3y/3 = -x/3

y = -1/3 x

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Evaluate tan(sin^-1(-4/5)). Enter your answer as a fraction using the slash bar (/).
Anvisha [2.4K]

Answer:

-1333/1000

Step-by-step explanation:

Evaluate tan(sin^-1(-4/5)).

First we need to evaluate the expression in parenthesis

sin^-1(-4/5)

= sin^-1(-0.8)

= -53.13

SUbstitute the given value into the original expression as shown;

tan(sin^-1(-4/5))

=  tan(-53.13)

= -1.333

= -1333/1000

Hence the required answer is  -1333/1000

8 0
2 years ago
Read 2 more answers
Explain why the exponents cannot be added in the product 12^3 x 11^3
cestrela7 [59]
The exponent cannot be added to the product because it stated in the law of exponents. An exponent is simply the shorthand in multiplying your base number. Exponent will give how many times you will multiply the base numbers. It is not possible that you add both exponents in the given situation because they have different value together.
=> 12^3 x 11^3
If we solve this equation following the rule of exponent will get the correct answer:
=> (12 x 12 x 12) x (11 x 11 x 11)
=> 1728 X 1331
=> the answer is 2 299 968
But if we add the exponent, the answer would be wrong
=> 12^3 x 11^3
=> 132^6
=> 5289852801024 which is wrong.



7 0
3 years ago
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If you spin the spinner below, what is the<br><br> probability that you will land on a 2 ?
REY [17]
What are all the numbers on the spinner
5 0
2 years ago
PLEASE HELP ILL GIVE BRAINIEST AND POINTS ASAP
miskamm [114]

Answer:

$1161

Step-by-step explanation:

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6 0
3 years ago
A 1000-liter (L) tank contains 500 L of water with a salt concentration of 10 g/L. Water with a salt concentration of 50 g/L flo
djverab [1.8K]

Answer:

a) y(t)=50000-49990e^{\frac{-2t}{25}}

b) 31690.7 g/L

Step-by-step explanation:

By definition, we have that the change rate of salt in the tank is \frac{dy}{dt}=R_{i}-R_{o}, where R_{i} is the rate of salt entering and R_{o} is the rate of salt going outside.

Then we have, R_{i}=80\frac{L}{min}*50\frac{g}{L}=4000\frac{g}{min}, and

R_{o}=40\frac{L}{min}*\frac{y}{500} \frac{g}{L}=\frac{2y}{25}\frac{g}{min}

So we obtain.  \frac{dy}{dt}=4000-\frac{2y}{25}, then

\frac{dy}{dt}+\frac{2y}{25}=4000, and using the integrating factor e^{\int {\frac{2}{25}} \, dt=e^{\frac{2t}{25}, therefore  (\frac{dy }{dt}+\frac{2y}{25}}=4000)e^{\frac{2t}{25}, we get   \frac{d}{dt}(y*e^{\frac{2t}{25}})= 4000 e^{\frac{2t}{25}, after integrating both sides y*e^{\frac{2t}{25}}= 50000 e^{\frac{2t}{25}}+C, therefore y(t)= 50000 +Ce^{\frac{-2t}{25}}, to find C we know that the tank initially contains a salt concentration of 10 g/L, that means the initial conditions y(0)=10, so 10= 50000+Ce^{\frac{-0*2}{25}}

10=50000+C\\C=10-50000=-49990

Finally we can write an expression for the amount of salt in the tank at any time t, it is y(t)=50000-49990e^{\frac{-2t}{25}}

b) The tank will overflow due Rin>Rout, at a rate of 80 L/min-40L/min=40L/min, due we have 500 L to overflow \frac{500L}{40L/min} =\frac{25}{2} min=t, so we can evualuate the expression of a) y(25/2)=50000-49990e^{\frac{-2}{25}\frac{25}{2}}=50000-49990e^{-1}=31690.7, is the salt concentration when the tank overflows

4 0
3 years ago
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