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3 years ago

Could someone tell me if i’m correct

Chemistry

2 answers:

vladimir1956 [14]3 years ago

7 0

Yeahh you should be anyways!!

Yanka [14]3 years ago

4 0

Yea your correct
Good Luck :)

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Is this equation balanced and in the lowest form? 4NH3 → 2N2 + 6H2

solong [7]

Answer:

B.) No, because the coefficients could be reduced to 2,1, and 3.

Explanation:

The equation is not in its lowest molar ratio form. In this case, all of the coefficients can be divided by 2 and still result in whole numbers.

As such, the correct balanced equation is:

2 NH₃ ----> N₂ + 3 H₂

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2 years ago

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Viktor [21]

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3 years ago

Which topic is commonly used to explain activation energy and how chemical reactions happen

castortr0y [4]

The correct answer is collision theory

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4 years ago

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What characteristic of gases makes them different from liquids or solids?

Marrrta [24]

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3 years ago

Suppose a sample of gas is composed of 100 molecules, with speeds given below. Speed (m/s) Number 200 23 400 42 600 26 800 8 100

ollegr [7]

Answer:

The answer is:

$speed(\frac{m}{s}) \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (number)\\\\ 100 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 23 \\\\ 200 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 42 \\\\ 300 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 26 \\\\ 400 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 8 \\\\ 500 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 1 \\\\$

Explanation:

Its total kinetic energy of a gas colloquial atom colloction is equal to absolute temperature alone, according to the programs that directly gas Theory.

Average speed for 1st option:

$= \frac{(200 \times 23)+(400 \times 42)+(600 \times 26)+(800 \times 8) +1000}{100} \\\\= 444\ \frac{m}{s} \ \ \ \ \ \ \ \ \ \text{average speed of gas}$

Average speed for 2nd option:

$= \frac{(200 \times 11) +(400 \times 21)+ (600 \times 13)+ (800 \times 4)}{11+21+13+4} \\\\= 440 \ \frac{m}{s}$

Average speed for 3rd option:

$= \frac{(200 \times 43) +(400 \times 50)+ (600 \times 7)}{100} \\\\ =328 \ \frac{m}{s}$

Average speed for 4th option:

$= \frac{(200 \times 50) +(400 \times 25)+ (600 \times 13)+(800\times 8)+(1000 \times 4)}{100}\\\\ =382\ \frac{m}{s}$

Average speed for 5th option:

$= \frac{(100 \times 23) +(200 \times 42)+ (300 \times 26)+(400\times 8)+500}{100}\\\\ =222 \ \frac{m}{s}$

The average speed also increased by half because the temperatures had kinetic energy. $\to 444 \ \frac{m}{s}\ to \ 222 \ \frac{m}{s}$

7 0

3 years ago