C because it is and I know
Answer is D
Balance the equation
The absorbance reported by the defective instrument was 0.3933.
Absorbance A = - log₁₀ T
Tm = transmittance measured by spectrophotometer
Tm = 0.44
Absorbance reported in this equipment = -log₁₀ (0.44) = 0.35654
True absorbance can be calculated by true transmittance, Tm = T+S(α-T)
S = fraction of stray light = 6%= 6/100 = 0.06
α= 1, ideal case
T = true transmittance of the sample
Tm = T+S(α-T)
now, T= Tm-S/ 1-S = 0.44-0.06/ 1-0.06 = 0.404233
therefore, actual reading measured is A = -log₁₀ T = -log₁₀ (0.404233)
i.e; 0.3933
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The major visible difference between<span> the two are crystal size, </span>intrusive rocks<span> have a larger crystal/grain texture due to the slow cooling of magma below the earth surface which encourages the growth of larger crystals, while </span>extrusive rocks<span>, because of the rapid cooling at/above the earth's surface does the opposite. Hope I helped</span>
Science of, or study of contours, or the lines outlining a scene, drawing, etc.
