Answer:
Therefore the required point A(x₁ , y₁) = A( -3 , 4 )
Step-by-step explanation:
Given:
The midpoint of segment AB is M(1,-3)
and B(5,-10),
Let
point A( x₁ , y₁)
point B( x₂ , y₂) ≡ (5 , -10)
M(x , y) = (1 , -3 )
To Find:
point A( x₁ , y₁) = ?
Solution:
M is the midpoint of segment AB. {Given}
BY Mid point Formula we have
Substituting the given values in above equation we get
Therefore the required point A(x₁ , y₁) = A( -3 , 4 )
Https://www.tiger-algebra.com/drill/(3x~2−5xy_2y~2)−(7x~2−3xy−3y~2)/
3 odd integers have a property that they average up to the middle large one. Let's say we have 3, 5, and 7. 3 is 2 less than 5 and 7 is 2 more than 5. so when you add them it equals 2 times 5.
After we know that, the sum of 3 odd integers is just 3 times the middle number. ex. 3+5+7 = 3 times 5 = 15
Then we know the some number times three = 225. we find out that the middle number is 75, so the other two are 73 and 77
Answer:
The rule to be use is
SOC CAH TOA
But in this we use d CAH cox there's adjacent and hypothenos here
Step-by-step explanation:
The first triangle
hyp²=opp.²+adj²
62²=x²+3.5²
x²=62²-3.5²
x²=3844-12.25
x²=3831.75
Answer:
I think the answer is c if i am not mistaken
Step-by-step explanation: