When I get multiplied by any number, the sum of the figures in the product is always me. What am I?
2 answers:
I am the number '9'
To prove:
On multiplying 9 with different numbers, the sum of the digits of its product is always 9. Let's see;
9 * 2 = 18
where (1 + 8 = 9)
Now, multiplying it by 3
9 * 3 = 27
where (2 + 7 = 9)
Similarly,
9 * 4 = 36
where (3 + 6 = 9)
9 * 5 = 45
where (4 + 5 = 9)
9 * 6 = 54
where (5 + 4 = 9)
9 * 7 = 63
where (6 + 3 = 9).
Thus, option b i.e. 9 is the correct answer.
Learn more about 'numbers' here:
brainly.in/question/24738334
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Answer:
1980
We can choose 2 men from 9 in 36 in ways.
We can choose 2 women from 11 in 55 ways.
For any arrangement of 2 men there are 55 ways of combining them with 2 women => 55 * 36 = 1980 total ways.
If you're wondering how i got the numbers i used the combination formula:
C(n, k) =