$(x^3-8x^2+19x-9)\div(x-4)=x^2-4x+3\\\underline{-x^3+4x^2}\\=-4x^2+19x\\\underline{\ \ \ \ \ 4x^2-16x}\\.\ \ \ =3x-9\\\underline{\ \ \ \ \ -3x+12}\\.\ \ \ \ \ =\ 3$

$x^3-8x^2+19x-9=(x^2-4x+3)(x-4)+3$

6 0

3 years ago

A perfectly cylindrical candle has a volume of 125.6 cubic inches. Find the area of its base if the height is 10 inches

il63 [147K]

12.56 inches

10×12.56=125.6

8 0

3 years ago

Is this a good math essay?

astra-53 [7]

Answer:

I'm just going to assume that your answer is correct since you didn't attach the question. If you are submitting this to your teacher then you are going to want to have correct spelling and grammar. The slang usage isn't professional, but if your teacher is fine with it then you should only worry about spelling. Hope this helped you!!

7 0

3 years ago