Answer:
0.965925826 = 0.97
Step-by-step explanation:
just put in the calculator >>> cos(15)
Let stadium 1 be the one on the left and stadium 2 the one on the right.
Angle above stadium 1 is 72.9° and the angle above stadium 2 is 34.1° using the angle property of alternate angles(because both the ground and the dotted line are parallel).
For the next part we need to use the trigonometric function of tangent.
As tan x = opposite / adjacent,
Tan 72.9°=1500/ adjacent ( the ground from O to stadium 1)
Therefore the adjacent is 1500/tan 72.9°= 461.46 m( to 5 s.f.)
Same for the next angle,
Tan 34.1°=1500/ adjacent ( the ground from O to stadium 2)
Therefore, the adjacent is 1500/tan 34.1° = 2215.49 m (to 5 s.f.)
Thus, the distance between both stadiums is 2215.49-461.46= 1754.03 m
Correcting the answer to whole number gives you 1754 m which is the option C.
Answer:
$60,890 is the cost of new truck.
Step-by-step explanation:
Given :
Purchasing cost of truck =$55000.
Sales Tax=$4000
Painted logo cost = $1600
Safety testing cost =$290.
Then the Cost of truck can be determined by

What is the question to your problem? Sorry...
Topic : Linear equations in two variables.
Given :
- 2x - y = 3 ––– (i)
- - x - y = 3 ––– (ii)
Solution :
Now,
(i) – (ii)




Now, substituting the value of x in Eq (i) :




Therefore,
- <u>The value of x = 0 and y = -3</u>