Answer:
Actual yield = 20.52 g
Explanation:
Given data:
Theoretical yield = 25.3 g
Percentage yield = 81.1 %
Actual yield = ?
Solution:
Formula:
Percentage yield = Actual yield /theoretical yield × 100
81.1 % /100 = Actual yield / 25.3 g
0.811 = Actual yield / 25.3 g
Actual yield = 0.811 × 25.3 g
Actual yield = 20.52 g
Explanation:
Mole ratio of Oxygen to Hydrogen gas = 1 : 2.
If we use 3.0 moles of oxygen gas, we would need 3.0 * 2 = 6.0 mol of hydrogen gas.
However we only have 4.2 mol of hydrogen. Therefore hydrogen is limiting and oxygen is in excess. (B)
<h2>Mass preservation.</h2>
Explanation:
- Mass of the system must remain the same over time, as the system's mass cannot alter according to the law of preservation of mass for any closed system.
Landolt Experiment -
- Landolt was German chemist, He demonstrated the law of preservation of mass experimentally by utilizing H- glass tube filled with silver nitrate in appendage A and HCl corrosive in appendage B.
- The reactants were blended and a white accelerate of Silver chloride was shaped alongside nitric corrosive. The tube is weighed once more.
Answer:
MCO3 is BaCO3
The mass of CO2 produced is 0.28g of CO2
Explanation:
The first step in solving the question is to put down the balanced reaction equations as shown in the image attached. Secondly, we obtain the relative number of moles acid and base as mentioned in the question. The balanced neutralization reaction equation is used to obtain the number of moles of excess acid involved in the neutralization reaction.
This is then subtracted from the total number of moles acid to give the number of moles of acid that reacted with MCO3. From here, the molar mass of MCO3 and identity of M can be found. Hence the mass of CO2 produced is calculated as shown.
