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Andrej [43]
3 years ago
12

THIS IS FOR A QUIZ DUE IN 5 MINS

Chemistry
1 answer:
RideAnS [48]3 years ago
5 0

Answer:

12.18 u

Explanation:

The average atomic mass of an element is calculated by taking the weighted average of the atomic masses of its stable isotopes.

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What is the difference between elements, mixtures, and compounds?
MAXImum [283]

Answer:

If it is pure, the substance is either an element or a compound. If a substance can be separated into its elements, it is a compound. If a substance is not chemically pure, it is either a heterogeneous mixture or a homogeneous mixture. If its composition is uniform throughout, it is a homogeneous mixture.

6 0
4 years ago
6. The pOH of a solution of NaOH is 11.30. What is the [H+<br><br> ] for this solution?
sashaice [31]

Answer:

The [H⁺] for this soluton is 2*10⁻³ M

Explanation:

pH, short for Hydrogen Potential and pOH, or OH potential, are parameters used to measure the degree of acidity or alkalinity of substances.

The values ​​that compose them vary from 0 to 14 and the pH value can be directly related to that of pOH by means of:

pH + pOH= 14

In this case, pOH=11.30, so

pH + 11.30= 14

Solving:

pH= 14 - 11.30

pH= 2.7

Mathematically the pH is the negative logarithm of the molar concentration of the hydrogen or proton ions (H⁺) or hydronium ions (H₃O):

´pH= - log [H⁺] = -log [H₃O]

Being pH=2.7:

2.7= - log [H⁺]

[H⁺]= 10⁻² ⁷

[H⁺]=1.995*10⁻³ M≅ 2*10⁻³ M

<u><em>The [H⁺] for this soluton is 2*10⁻³ M</em></u>

8 0
4 years ago
The empirical formula for a compound is C2H4NO. If its molar mass is 232.2 g/mol, what is the molecular formula of the compound?
Irina18 [472]

Empirical formula mass

  • C2H4NO
  • 2(12)+4(1)+14+16
  • 30+24+4
  • 58g/mol

Molar mass=232.2g/mol

Find n

  • Molar mass/Empirical formula mass
  • 232.2/58
  • 4

Molecular formula

  • n×Empirical formula
  • 4(C2H4NO)
  • C8H16(NO)_4
4 0
2 years ago
PLEASE ROUND TO THE 2ND DECIMAL PLACE!!!
Digiron [165]
I don’t know ask you’re teacher
7 0
3 years ago
A 7.028 gram sample of a sodium sulfate hydrate is heated. After driving off all the water, 3.100 grams of the anhydrous salt is
Nady [450]

Answer:

NaSO_4.10H_2O

Explanation:

Given that:-

Mass of the hydrated salt = 7.028 g

Mass of the anhydrous salt = 3.100 g

Mass of water eliminated = Mass of the hydrated salt - Mass of the anhydrous salt = 7.028 - 3.100 g = 3.928 g

<u>Moles of water: </u>

Mass of water = 3.928 g

Molar mass of H_2O = 18 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus, moles are:

moles= \frac{3.928\ g}{18\ g/mol}

moles_{water}= 0.2212\ mol

<u>Moles of anhydrous salt: </u>

Amount = 3.100 g

Molar mass of NaSO_4 = 142.04 g/mol

Thus, moles are:

moles= \frac{3.100\ g}{142.04\ g/mol}

moles_{CaSO_4}= 0.02182\ mol

The simplest ratio of the two are:

NaSO_4:H_2O =0.02182 :  0.2212 = 1 : 10

<u>Hence, the formula for hydrate is:- NaSO_4.10H_2O</u>

7 0
3 years ago
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