Evaporating? But that’s with a boiling liquid
(a) at the bottom - high density organic compound dissolved in methylene chloride
(b) at the bottom - saturated aqueous sodium chloride
Explanation:
Sodium chloride is dissolved in water while the organic compounds are dissolved in methylene chloride. After mixing the two solutions two layers will form because water (polar molecule) will not mix with the methylene chloride (nonpolar molecule).
The layer with higher density will be at the bottom.
(a) saturated aqueous sodium chloride (d = 1.2 g/mL) - upper layer
high density organic compound dissolved in methylene chloride (d = 1.4 g/mL) - bottom layer
(b) saturated aqueous sodium chloride (d = 1.2 g/mL) - bottom layer
low density organic compound dissolved in methylene chloride (d = 1.1 g/mL) - upper layer
Learn more about:
liquids with different densities
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Answer:
We need 7.5 mL of the 1M stock of NaCl
Explanation:
Data given:
Stock = 1M this means 1 mol/ L
A 0.15 M solution of 50 mL has 0.0075 moles NaCl per 50 mL
Step 2: Calculate the volume of stock we need
The moles of solute will be constant
and n = M*V
M1*V1 = M2*V2
⇒ with M1 = the initial molair concentration = 1M
⇒ with V1 = the volume we need of the stock
⇒ with V2 = the volume we want to make of the new solution = 50 mL = 0.05 L
⇒ with M2 = the concentration of the new solution = 0.15 M
1*V1 = 0.15*(50)
V1 = 7.5 mL
Since 0.0075 L of 1M solution contains 0.0075 moles
50 mL solution will contain also 0.0075 moles but will have a molair concentration of 0.0075 moles / 0.05 L =0.15 M
We need 7.5 mL of the 1M stock of NaCl
False. gases have to greatest freedom of motion
