Find a numerical value if one trigonometric function of x if tan2x-sin2x/sin2x=5

Mathematics

1 answer:

seropon [69]3 years ago

4 0

Answer:

The values of x that satisfy the given equation are:

x1 = 1.183 + nπ

x2 = -1.183 + nπ

Step-by-step explanation:

Given tan²x - sin²x/sin²x = 5

Simplifying this, we have

tan²x - 1 = 5

Adding 1 to both sides, we have

tan²x = 6

Because tan²x = (tanx)², we can write as

(tanx)² = 6

Taking square roots of both sides, we have.

tanx = ±√6

x = arctan(±√6) + nπ

≈ 1.183 + nπ or -1.183 + nπ

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steposvetlana [31]

Answer:

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Step-by-step explanation:

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From here, you must find the two factors of -24 (the first and third terms' coefficients multiplied together) that add up to 2 (the middle terms coefficient)

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3 years ago

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72/63 in simplest form

Viktor [21]

$\frac{72}{63}$
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3 years ago

In the equation z/6 =

Nikitich [7]

Hi there!

»»————-　★　————-««

I believe your answer is:

"Isolate the variable using inverse operations."

»»————-　★　————-««

Here’s why:

To solve for a variable, we would have to isolate it on one side.

To isolate it, we would use inverse operations on both sides on the equation until the variable is isolated.