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mote1985 [20]
3 years ago
8

Find a numerical value if one trigonometric function of x if tan2x-sin2x/sin2x=5

Mathematics
1 answer:
seropon [69]3 years ago
4 0

Answer:

The values of x that satisfy the given equation are:

x1 = 1.183 + nπ

x2 = -1.183 + nπ

Step-by-step explanation:

Given tan²x - sin²x/sin²x = 5

Simplifying this, we have

tan²x - 1 = 5

Adding 1 to both sides, we have

tan²x = 6

Because tan²x = (tanx)², we can write as

(tanx)² = 6

Taking square roots of both sides, we have.

tanx = ±√6

x = arctan(±√6) + nπ

≈ 1.183 + nπ or -1.183 + nπ

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Answer:

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(\stackrel{x_1}{-3}~,~\stackrel{y_1}{8})\hspace{10em} \stackrel{slope}{m} ~=~ -\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{8}=\stackrel{m}{-\cfrac{2}{3}}(x-\stackrel{x_1}{(-3)})\implies y-8=-\cfrac{2}{3}(x+3)

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