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mote1985 [20]
3 years ago
8

Find a numerical value if one trigonometric function of x if tan2x-sin2x/sin2x=5

Mathematics
1 answer:
seropon [69]3 years ago
4 0

Answer:

The values of x that satisfy the given equation are:

x1 = 1.183 + nπ

x2 = -1.183 + nπ

Step-by-step explanation:

Given tan²x - sin²x/sin²x = 5

Simplifying this, we have

tan²x - 1 = 5

Adding 1 to both sides, we have

tan²x = 6

Because tan²x = (tanx)², we can write as

(tanx)² = 6

Taking square roots of both sides, we have.

tanx = ±√6

x = arctan(±√6) + nπ

≈ 1.183 + nπ or -1.183 + nπ

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The results of the composite functions are:

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  • g(f(x)) = 6x - 9

<h3>What are composite functions?</h3>

Composite functions are functions that are obtained by combining two or more functions together

Assume that:

  • f(x) = 2x - 3
  • g(x) = 3x

Then the computation of the composite functions are as follows:

<h3>Function (f * g)(x)</h3>

(f \times g)(x) = f(x) \times g(x)

(f \times g)(x) = (2x-3) \times (3x)

(f \times g)(x) = 6x^2-9x

<h3>Function f(g(x))</h3>

We have: f(x) = 2x - 3

This gives

f(g(x)) = 2g(x) - 3

So, we have:

f(g(x)) = 2(3x) - 3

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<h3>Function g(f(x))</h3>

We have: g(x) = 3x

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So, we have:

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