Answer:
μ = 1 The firm expects that one oil exploration will be successful.
v(x)= 0.9
Step-by-step explanation:
The first step is to define the random variable x as:
x: number of oil explorations being succesful
Then x can be take this values:
x = 0 , x =1 ... x =10
x is a binomially distributed random variable with parameters.
p = 0.1 and n=10
And the mean or the expected value of x is:
μ = E(x) = np
Then μ = 10*0.1 = 1
And the variance of x is:
V(x) = np(1-p)
V(x) = 10(0.1)(1-0.1)= 0.9
Answer:
free cash dog watr
Step-by-step explanation:
|DF| = |DE| + |EF|
|DF| = 9x -36
|DE| = 47
|EF| = 3x+10
Substitute:
9x - 39 = 47 + 3x + 10
9x - 39 = 3x + 57 |+39
9x = 3x + 96 |-3x
6x = 96 |:6
x = 16
Put the value of x to the equation |EF| = 3x + 10
|EF| = (3)(16) + 10 = 48 + 10 = 58
Answer: |EF| = 58
5.09 because 2 is less then 5 so you round down
