Answer:
-11, -10, -9
Step-by-step explanation:
The middle one is their average, -30/3 = -10. The three integers are -11, -10, -9.
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I like to work "consecutive integer" problems using the average value of the integers involved. The average of <u>two</u> consecutive integers is 1/2 more than the small one, and 1/2 less than the large one, for example. Here, there are <u>three</u> consecutive integers, so their average is the middle one.
If you want to write that using an equation, you can let x represent the middle integer. Then the sum is ...
(x -1) +(x) + (x+1) = 3x = -30
x = -30/3 = -10 . . . . . the same average we computed above.
x -1 = -11 . . . . . the smaller of the other two integers
x +1 = -9 . . . . . the larger of the other two integers
Divide each side by x so the x squared becomes a single x. On the other side you should get five, so your answer is:
X=5
Answer:
85%
Step-by-step explanation:
34/40 = 0.85
0.85 * 100 = 85
Answer: well, the answer can really be any two numbers, as long as y is one more than x. EXAMPLE: 16 = 15 + 1, 7 = 6 + 1, -54 = -55 + 1, etc
