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3 years ago

How do you solve this problem?

Mathematics

2 answers:

babymother [125]3 years ago

7 0

Let's solve your equation step-by-step.16(a−4)=13(2a+4)Step 1: Simplify both sides of the equation.16(a−4)=13(2a+4)(16)(a)+(16)(−4)=(13)(2a)+(13)(4)(Distribute)16a+−23=23a+43Step 2: Subtract 2/3a from both sides.16a+−23−23a=23a+43−23a−12a+−23=43Step 3: Add 2/3 to both sides.−12a+−23+23=43+23−12a=2Step 4: Multiply both sides by 2/(-1).(2−1)*(−12a)=(2−1)*(2)a=−4

solong [7]3 years ago

5 0

You do distributive property

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ruslelena [56]

Answer:

Step-by-step explanation:

6x+3

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3 years ago

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Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by

a_sh-v [17]

Answer:

Dimension of the box is $16.1\times 7.1\times 2.45$

The volume of the box is 280.05 in³.

Step-by-step explanation:

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the box?

Solution :

Let h be the height of the box which is the side length of a corner square.

According to question,

A sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

The length of the box is $L=21-2h$

The width of the box is $W=12-2h$

The volume of the box is $V=L\times W\times H$

$V=(21-2h)\times (12-2h)\times h$

$V=(21-2h)\times (12h-2h^2)$

$V=252h-42h^2-24h^2+4h^3$

$V=4h^3-66h^2+252h$

To maximize the volume we find derivative of volume and put it to zero.

$V'=12h^2-132h+252$

$0=12h^2-132h+252$

Solving by quadratic formula,

$h=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$h=\frac{-(-132)\pm\sqrt{132^2-4(12)(252)}}{2(12)}$

$h=\frac{132\pm72.99}{24}$

$h=2.45,8.54$

Now, substitute the value of h in the volume,

$V=4h^3-66h^2+252h$

When, h=2.45

$V=4(2.45)^3-66(2.45)^2+252(2.45)$

$V\approx 280.05$

When, h=8.54

$V=4(8.54)^3-66(8.54)^2+252(8.54)$

$V\approx -170.06$

Rejecting the negative volume as it is not possible.

Therefore, The volume of the box is 280.05 in³.

The dimension of the box is

The height of the box is h=2.45

The length of the box is $L=21-2(2.45)=16.1$

The width of the box is $W=12-2(2.45)=7.1$

So, Dimension of the box is $16.1\times 7.1\times 2.45$

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3 years ago

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marysya [2.9K]

Answer:

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3 years ago

What is the scale factor of two similar pyramids with volume of 13824 cubic feel and 216 cubic feet?

velikii [3]

Answer: The scale factor is 4

Step-by-step explanation:

We know that the pyramids are similar. The volume of one of these pyramids is 13,824 cubic feet and the volume of the other one is 216 cubic feet. Then:

$V_1=13,824ft^3\\V_2=216ft^3$