Once you know your basic operations addition<span>, </span>subtraction,multiplication<span>, </span>division <span>you will encounter story problems also known as word problems that require you to read a problem and decide which operation to perform in order to get the answer. There are key words here that often indicate which operation you will use. We will give you a list of them, but remember that for many problem</span><span>s </span><span>there may not be a key word and you’ll have to use your best judgment in order to figure out what to do. </span>
Answer:
80 cm^3 (cm cubed)
Step-by-step explanation:
5 x 2 x 8
Answer:JKL and ∠RST are complementary.
m∠JKL = 36° and m∠RST = ( x + 15)°.
Find the value of x and the measure of ∠RST .
complementary angles are two angles whose sum is 90°
36%2Bx+%2B+15=90°
51%2Bx+=90°
x+=90-51°
x+=39°
->the measure of ∠RST== ( 39 + 15)=54°
both answer and explanation
Answer:
D. b = r+z
Step-by-step explanation:
Given the expression b-r = z, we are to solve for b. To do this, we will add 'r' to both sides of the equation as shown;
b-r+r = z+r
Since -r+r = 0, substitute:
b+0 = z+r
b = z+r
Hence the resulting equation when r is added to both sides of the equation is b = z+r
Hence option D is correct
Answer:
Step-by-step explanation:
Given: Dimensions of a big locker are 0.5 m × 0.6 m × 1.2 m
Dimensions of a small locker are 0.5 m × 0.6 m × 
(as height of small locker is half the height of big locker )
To find: total volume of one big locker and one small locker
Solution:
Volume of cuboid = length × breadth × height
Total volume of one big locker and one small locker = Total volume of one big locker + total volume of one small locker
= 
