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MrRissso [65]
3 years ago
9

Suppose a van gets 22 mi/gal. The distance traveled D(g) is a function of the gallons of gas used

Mathematics
1 answer:
babymother [125]3 years ago
5 0

Answer:

a) Table and graph showed

b) The distance will be 231 miles

c) Yes

Step-by-step explanation:

We know the van gets 22 mi/gal, so the distance D in miles traveled by the van can be expressed as  

D(g)=22g, being g the number of gallons of gas used

a) The graph of the function D and its corresponding table of values is shown below.  

b) If the van used g=10.5 gallons of gas, the distance would be:

D(10.5)=22 x 10.5 = 231 miles

c) The values of g are real in nature because they represent the amount of gas consumed by the van and it can be any real positive number. Being D a linear function of g, it also happens to take positive real values. Then it makes sense to connect the points with lines.

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The semicircle shown at left has center X XX and diameter W Z ‾ ​WZ ​ ​​ start overline, W, Z, end overline. The radius X Y ‾ ​X
BabaBlast [244]
Triangle XYZ is equilateral, so the central angle of the sector is 120°, or 2π/3 radians. The area of a sector of central angle β is given by
.. A = (1/2)r^2*β . . . . . . β in radians
Your sector's area is
.. A = (1/2)*2^2*(2π/3) = 4π/3 . . . . square units
7 0
3 years ago
If the radius of the right cylinder is 5 in and the radius of the oblique cylinder is 4 in, they will have the same volume as lo
steposvetlana [31]

Answer:

False

Step-by-step explanation:

The volume of a right cylinder is given by the formula:

V=\pi r^2h

And the volume if a oblique cylinder is <em>also</em> given by the formula:

V=\pi r^2h

Regardless of the height, if the radius are different, then the volume would not be the same.

Algebraically:

\pi(4)^2h\neq\pi(5)^2h\\16\pi\neq25\pi

3 0
3 years ago
A stadium has 50,000 seats. Seats sell for $25 in section A, $20 in section B, and $15 in section C. The number of seats in sect
Novay_Z [31]

Answers:

section A = 25,000 seats

section B = 14,200 seats

section C = 10,800 seats

Your teacher may want you to leave out the commas from each number.

=============================================================

Work Shown:

  • A = number of seats in section A
  • B = number of seats in section B
  • C = number of seats in section C

A = B+C

A+B+C = 50,000

B+C+B+C = 50,000

2(B+C) = 50,000

B+C = 50,000/2

B+C = 25,000

C = 25,000 - B

25A + 20B + 15C = 1,071,000

25(B+C) + 20B + 15C = 1,071,000

25(25,000) + 20B + 15(25,000 - B) = 1,071,000

625,000 + 20B + 375,000 - 15B = 1,071,000

1,000,000 + 5B = 1,071,000

5B = 1,071,000 - 1,000,000

5B = 71,000

B = (71,000)/5

B = 14,200 is the number of seats in section B

C = 25,000 - B

C = 25,000 - 14,200

C = 10,800 is the number of seats in section C

A = B+C

A = 14,200 + 10,800

A = 25,000 is the number of seats in section A

--------------

Check:

A+B+C = 25,000+14,200+10,800 = 50,000

5 0
2 years ago
1. Which of the following measurements could be the three side lengths of a right triangle? a. 4 cm, 5 cm, 9 cm b. 12 cm, 20 cm,
HACTEHA [7]

Answer:

b and c

Step-by-step explanation:

The Triangle Inequality Theorem lets us know that the sum of the two shortest sides of the triangle must be greater than the third side of the triangle.

In both A and D, the sum of the shortest two sides are equal to, not greater than the third side, so they will not form a triangle.

In B, 12+20 is 32, which is greater than 25. And in C, 18+24 is 42, which is greater than 30, so they both will form a triangle.

8 0
3 years ago
What is the square root of 5 divided by the square root of 15 and simplify and in fraction form​
ozzi

Answer:

\sqrt{\frac{1}{3} }

or

\frac{\sqrt{3} }{3}

Step-by-step explanation:

The expression \frac{\sqrt{5} }{\sqrt{15} } can be simplified by first writing the fraction under one single radical instead of two.

\frac{\sqrt{5} }{\sqrt{15} } = \sqrt{\frac{5}{15} }

5/15 simplifies because both share the same factor 5.

It becomes \sqrt{\frac{5}{15} } = \sqrt{\frac{1}{3} }

This can simplify further by breaking apart the radical.

\sqrt{\frac{1}{3} }  = \frac{\sqrt{1} }{\sqrt{3} }  = \frac{1}{\sqrt{3} }

A radical cannot be left in the denominator, so rationalize it by multiplying by √3 to numerator and denominator.

\frac{1}{\sqrt{3} } *\frac{\sqrt{3} }{\sqrt{3} }  =\frac{\sqrt{3} }{3}

4 0
3 years ago
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