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3 years ago

If your making $802 per week, how much money will you make per month?

Mathematics

2 answers:

navik [9.2K]3 years ago

5 0

The answer would be 3484.69
Because
$802 * 4.345

Hope this helps

Have a great day/night

dusya [7]3 years ago

4 0

Answer:

$3,208

Step-by-step explanation:

If you are asking without including taxes this would be your answer. There are four weeks in a month, so you would multiply 802 by 4.

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Donna wants to wrap a shipping box shaped like a rectangular prism. The box is 22 inches tall and has a square base with sides t

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Answer:

110

Step-by-step explanation:

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3 years ago

What is the maximum percent of net spendable income that should be set aside for housing

stepladder [879]

Answer:

Answer;

-38 %

Step-by-step explanation:

Explanation;

-Budget busters are the large potential problem areas that can destroy a budget. Failure to control even one of these problem areas can result in financial disaster.

-Housing takes about 38 percent of your monthly budget. Housing decisions should be based on need and financial ability, not on internal or external pressure.

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7 0

3 years ago

Read 2 more answers

What is 5/48 into a decimal

Mashutka [201]

5/48=0.1041666666666666666666666666666666666666666666666666666

7 0

3 years ago

Write an equation in standard form using integers Y= - x — 5

kykrilka [37]

Answer:

x + y = - 5

Step-by-step explanation:

The equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

Given

y = - x - 5 ( add x to both sides )

x + y = - 5 ← in standard form

8 0

3 years ago

The students in Mr. Wilson's Physics class are making golf ball catapults. The

Mnenie [13.5K]

Answer:

Part a) About 48.6 feet

Part b) About 8.3 feet

Part c) The domain is $0 \leq x \leq 48.6\ ft$ and the range is $0 \leq y \leq 8.3\ ft$

Step-by-step explanation:

we have

$y=-0.014x^{2} +0.68x$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

where

x is the ball's distance from the catapult in feet

y is the flight of the balls in feet

Part a) How far did the ball fly?

Find the x-intercepts or the roots of the quadratic equation

Remember that

The x-intercept is the value of x when the value of y is equal to zero

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-0.014x^{2} +0.68x=0$

$a=-0.014\\b=0.68\\c=0$

substitute in the formula

$x=\frac{-0.68(+/-)\sqrt{0.68^{2}-4(-0.014)(0)}} {2(-0.014)}$

$x=\frac{-0.68(+/-)0.68} {(-0.028)}$

$x=\frac{-0.68(+)0.68} {(-0.028)}=0$

$x=\frac{-0.68(-)0.68} {(-0.028)}=48.6\ ft$

therefore

The ball flew about 48.6 feet

Part b) How high above the ground did the ball fly?

Find the maximum (vertex)

$y=-0.014x^{2} +0.68x$

Find out the derivative and equate to zero

$0=-0.028x +0.68$

Solve for x

$0.028x=0.68$

$x=24.3$

Alternative method

To determine the x-coordinate of the vertex, find out the midpoint between the x-intercepts

$x=(0+48.6)/2=24.3\ ft$

To determine the y-coordinate of the vertex substitute the value of x in the quadratic equation and solve for y

$y=-0.014(24.3)^{2} +0.68(24.3)$

$y=8.3\ ft$

the vertex is the point (24.3,8.3)

therefore

The ball flew above the ground about 8.3 feet

Part c) What is a reasonable domain and range for this function?

we know that

A reasonable domain is the distance between the two x-intercepts

$0 \leq x \leq 48.6\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 48.6 feet

A reasonable range is all real numbers greater than or equal to zero and less than or equal to the y-coordinate of the vertex

we have the interval -----> [0,8.3]

$0 \leq y \leq 8.3\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 8.3 feet

8 0

3 years ago