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OverLord2011 [107]
3 years ago
14

If your making $802 per week, how much money will you make per month?

Mathematics
2 answers:
navik [9.2K]3 years ago
5 0
The answer would be 3484.69
Because
$802 * 4.345

Hope this helps

Have a great day/night
dusya [7]3 years ago
4 0

Answer:

$3,208

Step-by-step explanation:

If you are asking without including taxes this would be your answer. There are four weeks in a month, so you would multiply 802 by 4.

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Well, considering the amount of gravity placed on a kitten on the 4th of June, the answer would be 42
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igomit [66]

Answer:

its a statistical question

Step-by-step explanation:

Statistics is a branch of mathematics that deals with collecting, analyzing, and interpreting information

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******ANSWER ASAP PLEASE******
Lemur [1.5K]

(1/4)^-2 - (5^0 x 2) x 1^-1 =

(4/1)^2 - (1 x 2) x 1 = 16-2 = 14

If you raise something to the power of -2, swap numerator and denominator and remove the minus.

So (1/4)^-2 = 4^2 = 16

Also 1^-1 is just 1, not -1.

8 0
3 years ago
A student S is suspected of cheating on exam, due to evidence E of cheating being present. Suppose that in the case of a cheatin
Kay [80]

Answer:

Step-by-step explanation:

Suppose we think of an alphabet X to be the Event of the evidence.

Also, if Y be the Event of cheating; &

Y' be the Event of not involved in cheating

From the given information:

P(\dfrac{X}{Y}) = 60\% = 0.6

P(\dfrac{X}{Y'}) = 0.01\% = 0.0001

P(Y) = 0.01

Thus, P(Y') \ will\ be = 1 - P(Y)

P(Y') = 1 - 0.01

P(Y') = 0.99

The probability of cheating & the evidence is present is = P(YX)

P(YX) = P(\dfrac{X}{Y}) \ P(Y)

P(YX) =0.6 \times 0.01

P(YX) =0.006

The probabilities of not involved in cheating & the evidence are present is:

P(Y'X) = P(Y')  \times P(\dfrac{X}{Y'})

P(Y'X) = 0.99  \times 0.0001 \\ \\  P(Y'X) = 0.000099

(b)

The required probability that the evidence is present is:

P(YX  or Y'X) = 0.006 + 0.000099

P(YX  or Y'X) = 0.006099

(c)

The required probability that (S) cheat provided the evidence being present is:

Using Bayes Theorem

P(\dfrac{Y}{X}) = \dfrac{P(YX)}{P(Y)}

P(\dfrac{Y}{X}) = \dfrac{P(0.006)}{P(0.006099)}

P(\dfrac{Y}{X}) = 0.9838

5 0
3 years ago
NEEEEEEEDDDD HELPPPPPPP ASAPPPPPPPPP
Anni [7]

The true statement about the diagram is (a) IJ ≅ JG

<h3>How to determine the true statement?</h3>

From the question, we understand that:

KH bisects line IG at point J

This means that:

Line segment IG is divided into two equal parts, and point J is the middle

So, we have:

IJ ≅ JG

Hence, the true statement about the diagram is (a) IJ ≅ JG

Read more about perpendicular bisector at:

brainly.com/question/24753075

#SPJ1

8 0
2 years ago
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