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Answer:
no solutions
Step-by-step explanation:
4x + 2y = –14
6x + 3y = –22
Divide the first equation by 2 and the second equation by 3
4x/2 + 2y/2 = –14/2 2x +y = -7
6x/3 + 3y/3 = –22/3 2x + y = -22/3
The left hand sides are the same but the right hand sides are different.
Multiply the second equation by -1
2x+y = -7
-2x -y = 22/3
-------------------
0 = -7+22/3
0 = 1/3
This is never true, so there are no solutions
Answer:V/H=I
Step-by-step explanation:
v=IH
V/H=I
Answer:
-16/65
Step-by-step explanation:
Given sinα = 3/5 in quadrant 1;
Since sinα = opp/hyp
opp = 3
hyp = 5
adj^2 = hyp^2 - opp^2
adj^2 = 5^2 = 3^2
adj^2 = 25-9
adj^2 = 16
adj = 4
Since all the trig identity are positive in Quadrant 1, hence;
cosα = adj/hyp = 4/5
Similarly, if tanβ = 5/12 in Quadrant III,
According to trig identity
tan theta = opp/adj
opp = 5
adj = 12
hyp^2 = opp^2+adj^2
hyp^2 = 5^2+12^2
hyp^2 = 25+144
hyp^2 = 169
hyp = 13
Since only tan is positive in Quadrant III, then;
sinβ = -5/13
cosβ = -12/13
Get the required expression;
sin(α - β) = sinαcosβ - cosαsinβ
Substitute the given values
sin(α - β) = 3/5(-12/13) - 4/5(-5/13)
sin(α - β)= -36/65 + 20/65
sin(α - β) = -16/65
Hence the value of sin(α - β) is -16/65
Answer:
-15
Step-by-step explanation: the only numbers that can be used under a 0 is negative and since its colder it goes down -15+0 is -15
