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The answer to the question

Answer 1

The required equation of line parallel to given line is:$y = \frac{5}{6}x-8$

Step-by-step explanation:

Given equation of line is:

$y = \frac{5}{6}x+1$

As the equation of line is in slope-intercept form, the co-efficient of x s the slope

Let m1 be the slope of given line

m1= 5/6

Let m2 be the slope of new line

As the slopes of two parllel lines are equal, so

m1 = m2

m2 = 5/6

The slope intercept form is:

$y= m_2x+b$

Put m2 = 5/6 in equation

$y = \frac{5}{6}x+b$

Putting the point in the equation

$2 = \frac{5}{6}(12)+b\\2=10+b\\b = 2-10\\b = -8$

Putting the value of b, we get

$y = \frac{5}{6}x-8$

Hence,

The required equation of line parallel to given line is:$y = \frac{5}{6}x-8$

Keywords: Slope intercept form, equation of line

Learn more about equation of line at:

• brainly.com/question/1493255
• brainly.com/question/1491432

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