In a parallel circuit, ET = 120 V, R = 470 Ω, and XL = 500 Ω. What is the reactive power?
1 answer:
Answer:
Reactive power is 28.8VARs
Step-by-step explanation:
We are given that in a parallel circuit, ,R=470Ω and
=500Ω
And we area asked to find reactive power.
Reactive power is power dissipated due to reactive elements in the circuit and it occurs when voltage and current are not in phase.
Reactive power =
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It can be expected about 36.79% of chance that repair time exceeds
The probability that a repair time exceeds 15 hours is 0.3679
What is the exponential distribution?
It explains about the time between events or the distance between two random events is termed the exponential distribution. Here, the occurrence of the events is continuous and also independent. Moreover, the average rate is constant.
The cumulative distribution function of T is obtained below:
From the information given, let the random variable T be the required time to repair a machine follows exponential distribution with parameter λ
with mean. 1/2 hours
That is, E(x) = 1/2 hours.
The parameter of the random variable T is,
E(x) = 1/λ
λ = 1/E(x)
= 1/(1/2)
= 2
The probability density function of T is,
The cumulative density function of T is,
FT(t) = P(T <= t)
The CDF of T is,
P(T <= t) 0 <= T <= ∞
= 0 otherwise
to obtain the probability that a repair time exceeds
1/2 hours.
(a) The probability that a repair time exceeds 1/2 hours.
From the given information, the CDF of T is,
P(T <= t) 0 <= T <= ∞
= 0 otherwise
The required probability is,
P(T <= 1/2) = 1 - P(T <= 1/2)
= 1 - [ ]
= 0.3679
om total probability. It can be expected about 36.79% of chance that repair time exceeds
P(X => x) = 1 - P(X < x)
to obtain the probability that a repair takes at least 12.5 hours given that its duration exceeds 12 hours.
(b), The probability that a repair takes at least 12.5 hours given that its duration exceeds 12 hours is obtained below:
From the given information, the CDF of T is,
P(T <= t) 0 <= T <= ∞
= 0 otherwise
The required probability is,
P = P(T => 12.5∩T>12) / P(T>12)
= 0.3679
The probability that a repair takes at least 12.5 hours given that its duration exceeds 12 hours is obtained by dividing the
P = P(T => 12.5∩T>12) / P(T>12)
with
P(T>12).
It can be expected about 36.79% of chance that a repair takes at least 12.5 hours given that its duration exceeds 12 hours.
Hence, It can be expected about 36.79% of chance that repair time exceeds,
The probability that a repair time exceeds 15 hours is 0.3679
To learn more about the product of the fraction visit,
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Answer:
619.13 feet
Step-by-step explanation:
Please find the attachment.
Let x represent the distance between doghouse to the foot of the tower.
We have been given that from the top of a vertical tower, 331 feet above the surface of the earth, the angle of depression to a doghouse is 28 degrees 8'. We are asked to find the distance between doghouse to the foot of the tower.
First of all, we will convert our given angle into degrees as it is given in degrees and minutes.
We will divide 8 by 60 to convert 8 minutes into degrees as:
The doghouse, tower and angle of depression forms a right triangle with respect to ground, where, 331 feet is opposite side and x is adjacent side to angle 28.13 degrees.
Upon rounding to nearest hundredth, we will get:
Therefore, the doghouse is 619.13 feet far from the foot of the tower.
