In the case above, Talib work is not correct as one need to first switch x and y before one can solve for y.
<h3>What is the variables about?</h3>
Note that:
y=-8x+4
y-4=-8x
(y-4)/-8=x
Since the independent variable x is known, one can switch the variable labels and thus it will be:
y=(x-4)/-8
f^-1(x)=(x-4)/-8
This can be written again as:
f^-1(x)=(4-x)/8 :P
Thus one can say No, as he forgot to switch the variable labels after solving for the independent variable.
In the case above, Talib work is not correct as one need to first switch x and y before one can solve for y.
See the first part of the question below
Talib is trying to find the inverse of the function to the right. His work appears beneath it. Is his work correct? Explain your answer.
Learn more about variable from
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Answer:
Step-by-step explanation:
A, x=31
E, b=11
N, m=61
Y, b=15
I, a=80
G, k=-78
U, x=-13
R, u=88
O, y=13
A, w=104
H, d=-7
V, n=1/36
Sorry, don't want to give away all the answers!
Hope this helps!!!
What area of math is this,I may be able to help?
Answer: C) x = 2
2^{2x + 2} = 2^{3x}
Since both terms (above) have the same base, set the exponents to be equal:
2x + 2 = 3x (Rearrange to solve for x)
x = 2
∴ x = 2