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lisabon 2012 [21]
2 years ago
12

For pigs, the length of pregnancies varies according to a normal distribution with a mean of 114 days and a standard deviation o

f 5 days. According to the Empirical Rule, the length of approximately 68% of all pig pregnancies will fall between _____ and _____ days.
Mathematics
1 answer:
riadik2000 [5.3K]2 years ago
7 0

Answer: The length of approximately 68% of all pig pregnancies will fall between <u>109 days</u> and <u>119 days</u>.

Step-by-step explanation:

According to the empirical rule , 68% of the population falls within one standard deviations from the mean.

Given : For pigs, the length of pregnancies varies according to a normal distribution with a mean of 114 days and a standard deviation of 5 days.

According to the Empirical Rule, the length of approximately 68% of all pig pregnancies will fall between 114-1(5) days  and 114+1(5) days .

i.e. the length of approximately 68% of all pig pregnancies will fall between <u>109 days</u> and <u>119 days</u>.

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Complete question is;

The levels of mercury in two different bodies of water are rising. In one body of water the initial measure of mercury is 0.05 parts per billion (ppb) and is rising at a rate of 0.1 ppb each year. In the second body of water the initial measure is 0.12 ppb and the rate of increase is 0.06 ppb each year.

Which equation can be used to find y, the year in which both bodies of water have the same amount of mercury?

A) 0.05 – 0.1y = 0.12 – 0.06y

B) 0.05y + 0.1 = 0.12y + 0.06

C) 0.05 + 0.1y = 0.12 + 0.06y

D) 0.05y – 0.1 = 0.12y – 0.06

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Option C: 0.05 + 0.1y = 0.12 + 0.06y

Step-by-step explanation:

In the first body, the initial measure of mercury is 0.05 parts per billion (ppb) while it's rising at a rate of 0.1 ppb each year. We are told to use y for the number of years.

Thus, amount of mercury for y years in this first body is;

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Thus, amount of mercury for y years in this second body is;

A2 = 0.12 + 0.06y

Since we want to find the year in which both bodies of water have the same amount of mercury. Thus, it means;

A1 = A2

Thus;

0.05 + 0.1y = 0.12 + 0.06y

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