Write fractions in simplest form 3.6+{-2.4}

Several different cheeses are for sale. The cheese comes in wedges

Tpy6a [65]

Answer:

39.30 $cm^{2}$

Step-by-step explanation:

The area of the top surface of the wedge is the same as the area of a sector.

Area of a sector = (θ/ $360^{o}$ ) $\pi$ $r^{2}$

where: θ is the central angle, and r is the radius.

Given that: central angle = $45^{o}$ , radius = 10 centimetre.

Area of the top surface = Area of a sector = (θ/ $360^{o}$ ) $\pi$ $r^{2}$

= $\frac{45^{o} }{360^{o} }$ x $\frac{22}{7}$ x $(10)^{2}$

= $\frac{1}{8}$ x $\frac{22}{7}$ x 100

= 39.2857

= 39.30 $cm^{2}$

The area of the top surface of the wedge is 39.30 $cm^{2}$ .

3 0

3 years ago

Read 2 more answers

Write the expression 2 x 8 + 20 - 12 ÷ 6 with parentheses and brackets two different ways so one value is less than 10 and the o

Marizza181 [45]

Greater than 50:

2 x (8 + 20 - 12 / 8) is 52

Less than 10:

2 x (8 +(20 - 12)) ÷ 6 is 5.33

4 0

3 years ago

The germination rate is the rate at which plants begin to grow after the seed is planted.

chubhunter [2.5K]

Answer:

$z=\frac{0.467 -0.9}{\sqrt{\frac{0.9(1-0.9)}{15}}}=-5.59$

$p_v =P(z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of germinated seeds is significantly lower than 0.9 or 90%

Step-by-step explanation:

Data given and notation

n=15 represent the random sample taken

X=7 represent the number of seeds germinated

$\hat p=\frac{7}{15}=0.467$ estimated proportion of seeds germinated

$p_o=0.9$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion of germinated seeds is less than 0.9 or 90%.:

Null hypothesis: $p\geq 0.9$

Alternative hypothesis: $p < 0.9$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.467 -0.9}{\sqrt{\frac{0.9(1-0.9)}{15}}}=-5.59$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level assumed is $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of germinated seeds is significantly lower than 0.9 or 90%

4 0

3 years ago

Meryl spends a total of 68.82 for 2 pairs of sneakers with the same cost. the sales tax is 5.32. Meryl also uses a coupon for 3

Levart [38]

You subtract 3.00 which makes it 65.82, then you subtract 5.32 , which makes it 60.50 , then you divide by 2 , so your final Awnser is 30.25

7 0

4 years ago

What was the total cost of the ticket?

Vilka [71]

What ticket specifically are you talking about?

3 0

3 years ago