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Ugo [173]
3 years ago
5

Find the solutions to the following rational equations. 4x/x^2+x-6=7x/x^2-5x-24+3/x^2-10x+16

Mathematics
1 answer:
Mama L [17]3 years ago
4 0
<span><span>x =(-6-√44)/4=(-3-√<span> 11 </span>)/2= -3.158</span><span> x =(-6+√44)/4=(-3+√<span> 11 </span>)/2= 0.158</span></span>
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What is the equation of the line with an X intercept of negative 2 and Y intercept of one
forsale [732]

Answer:

y = 1/2x + 1

Step-by-step explanation:

Step 1: Find slope

(1-0)/(0+2) = 1/2

Step 2: Write equation

y = 1/2x + 1

8 0
4 years ago
Simplify the given expression below:
Dima020 [189]

Answer:

4) 8+2i

Step-by-step explanation:

When you expand you get 3+4i+5-2i

when you add the like terms you get 8+2i

5 0
3 years ago
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PLS I NEED HELP!! For each linear function graphed on the coordinate grid, enter the value of m and the value of b. Give your an
creativ13 [48]

Answer:

Red Line

m = 1/2

b = 1

Blue Line

m = 1

b = -1

Green Line

m = 3

b = 0

Step-by-step explanation:

First off, we need to know what m and b are first.

m is the slope

b means y-intercept, or, when x is 0

And to find slope use "m = y2 - y1/x2 - x1" (remember, Rise over Run, not Run over Rise!)

<u>Red line</u>: if you count it, you get a point on the line each time you go up once and to the right twice. We can use Rise over run. Rise is y, or its name, go up, which is the 1. then the run which is 2. So, the slope is 1/2 or m = 1/2. and we can see that the y-intercept is 1. m = 1/2, b = 1

<u>Blue Line</u>: This is pretty much the same as the red line, see the slope it's rise once and run once so, the slope is 1/1 which is 1. Then the y-intecept is b which is when x is 0, we check the y-axis line and we see that the y-intercept is -1. m = 1, b = -1

<u>Green Line</u>: And once again, the same as Red Line and Blue Line, the slope is 3. Rise is 3 times, run is once, so, 3/1 which is 3. While the y-intercept is 0 since it is on (0,0). Meaning that it goes through the origin. m = 3, b = 0

8 0
3 years ago
Pls halp im bad at math
Nostrana [21]

Answer:

what do you need help in

Step-by-step explanation:

4 0
3 years ago
If p q r is prime numbers such that pq+r=73, what is the least possible value of p+q+r
Jobisdone [24]
The answer to this question would be: p+q+r = 2 + 17 + 39= 58

In this question, p q r is a prime number. Most of the prime number is an odd number. If p q r all odd number, it wouldn't be possible to get 73 since
odd x odd + odd= odd + odd = even
Since 73 is an odd number, it is clear that one of the p q r needs to be an even number. 

There is only one odd prime number which is 2. If you put 2 in the r the result would be:
pq+2= 73
pq= 71
There will be no solution for pq since 71 is prime number. That mean 2 must be either p or q. Let say that 2 is p, then the equation would be: 2q + r= 73

The least possible value of p+q+r would be achieved by founding the highest q since its coefficient is 2 times r. Maximum q would be 73/2= 36.5 so you can try backward from that. Since q= 31, q=29, q=23 and q=19 wouldn't result in a prime number r, the least result would be q=17
r= 73-2q
r= 73- 2(17)
r= 73-34=39

p+q+r = 2 + 17 + 39= 58
6 0
3 years ago
Read 2 more answers
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