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ale4655 [162]
3 years ago
15

Which statement is true about these equations?

Mathematics
1 answer:
Troyanec [42]3 years ago
8 0

Answer:

a Equation A has a greater initial value.

Step-by-step explanation:

Equation A: y = 3x + 4

initial value: 4

rate of change: 3

Equation B: y = 5x + 2

initial value: 2

rate of change: 5

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In which quadrant will you find the point (-2,-2)
sineoko [7]

⊱________________________________________________________⊰

Answer:

  • Quadrant 3

Step-by-step explanation:

Points with both negative co-ordinates are found in the third quadrant.

\boxed{\begin{tabular}{c | 1} \sf{~~Quadrant 2 (-x,y)~~& Quadrant 1~ (x,y)~~} \\ \\\\\\\\\\\\ \cline{1-2} \sf{Quadrant \ 3 (-x,-y) \ & Quadrant \ 4 (x,-y)} \\\\\\\ \\\\\\\\\\\end{tabular}}

done !!

⊱_____________________________________________________⊰

6 0
2 years ago
If k stands for an integer, then is it possible for k2 + k to stand for an odd integer? Be prepared to justify your answer.
BartSMP [9]

Answer:

<em>k^2 + k never stands for an odd integer</em>

Step-by-step explanation:

Let us consider either case with which k stands for an odd or even integer;

Case 1: k is an odd integer

For integer a, k = 2a + 1

So, k + 1 = 2a + 2 = 2( a + 1 ) = 2b for integer b

k^2 + k = k ( k + 1 ) = k ( 2b ) = 2kb = 2c for integer c,

<em>Therefore, if k is an odd integer, then k^2 + k is an even integer ;</em>

Case 2: k is an even integer

For an integer a, k = 2a

So, k + 1 = 2a + 1

k^2 + k = k( k+1 ) = 2a( 2a + 1 ) , multiple of 2

<em>Therefore, if k is an even integer, then k^2 + k is an even integer;</em>

<em>This would make k^2 + k never stand for an odd integer</em>

5 0
3 years ago
My question is Multpiy (5 4/7)(-2 2/5) (idk what rational numbers are)
Nuetrik [128]

Answer:

Step-by-step explanation:

(39/7)(-12/5) = -468/35 = -13.37

4 0
3 years ago
Find the average rate of change of f(x)=4x^2-6 on interval [1,a]​
stiv31 [10]

9514 1404 393

Answer:

  4a +4

Step-by-step explanation:

The average rate of change of f(x) on the interval is ...

  (f(a) -f(1))/(a -1)

  = ((4a² -6) -(4(1)² -6))/(a -1) = (4a² -4)/(a -1)

  = 4(a² -1)/(a -1) = 4(a +1) = 4a +4

The average rate of change on the interval is 4a +4.

4 0
3 years ago
Describe the range of a square root function
Ket [755]
Range of square root function is from [0, infinity)
6 0
3 years ago
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