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3 years ago

I need x+y=5 and y=2x-4solved algebraically

Mathematics

2 answers:

ipn [44]3 years ago

7 0

X=3, y=2 solved algebraicly

schepotkina [342]3 years ago

4 0

Answer:

x = 3; y = 2

Step-by-step explanation:

x + y = 5

y = 2x - 4

Isolate the y in the first equation

y = 5 - x

y = 2x - 4

Substitute the values

5 - x = 2x - 4

Isolate the Variable

9 = 3x

Simplify

3 = x

Plug that into the first equation

3 + y = 5

Subtract 3 from both sides

y = 2

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Question 8 Find the unit vector in the direction of (2,-3). Write your answer in component form. Do not approximate any numbers

slamgirl [31]

Answer:

The unit vector in component form is $\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}} \right)$ or $\hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j$ .

Step-by-step explanation:

Let be $\vec u = (2,-3)$ , its unit vector is determined by following expression:

$\hat {u} = \frac{\vec u}{\|\vec u \|}$

Where $\|\vec u \|$ is the norm of $\vec u$ , which is found by Pythagorean Theorem:

$\|\vec u\|=\sqrt{2^{2}+(-3)^{2}}$

$\|\vec u\| = \sqrt{13}$

Then, the unit vector is:

$\hat{u} = \frac{1}{\sqrt{13}} \cdot (2,-3)$

$\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}} \right)$

The unit vector in component form is $\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}} \right)$ or $\hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j$ .

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Shalnov [3]

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3 years ago

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Ivan

Answer:

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Step-by-step explanation: