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Anna007 [38]
3 years ago
6

26plz I kind of get it

Mathematics
1 answer:
Leno4ka [110]3 years ago
6 0
I think you do

5c=120

5c/5 120/5 =24

you need to get c by itself so divide 5 . When you divide 5 by one side do it to the other


120/5=24


3. Answer 24
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Quadrilateral PQRS is a square whos side length is 10. Let X and Y be points outside the square so that XQ = YS = 6 and XP = YR
erik [133]

Answer:

392

Step-by-step explanation:

Triangles XQP and YRS are right triangles because triples 6, 8, 10 are Pythagorean triples.

Extend lines XQ, YR, YS and XP and mark their intersection as A and B.

Quadrilateral XAYB is a square because all right triangles PXQ, QAR, RYS and SBP are congruent (by ASA postulate) and therefore

  • all angles of the quadrilateral XAYB are right angles
  • all sides of XAYB are congruent and equal to 6 + 8 = 14 units.

Segment XY is the diagonal of the square XAYB, by Pythagorean theorem,

XY^2=XA^2+AY^2\\ \\XY^2=14^2+14^2\\ \\XY^2=196+196\\ \\XY^2=392  

3 0
3 years ago
-6 minus -2 1/2<br>step by step explanation please ​
tatuchka [14]

Turn fraction into a decimal.

-2 1/2 = -2.5

Remember that when you subtract a negative number it automatically changes it to adding a positive number.

-6 + 2.5 = -3.5

Hope This Helped! Good Luck!

7 0
3 years ago
Read 2 more answers
You want to enlarge a 4 x 5 inch photo to fit into a 1 inch wide frame
skelet666 [1.2K]

The 4•x by 5•x inner dimensions of the 53 inches outer perimeter picture frame, the 1 inch wide frame and the 4 × 5 inch picture to be enlarged, gives;

a. The outer perimeter equation is presented as follows;

18•x + 8 = 53 inches

b. The scale factor required for the enlargement of the picture is 2.5

<h3>Which method can be used to write the equation and find the scale factor?</h3>

The dimensions of the photo = 4 × 5 inch

Width of the frame = 1 inch

Outer perimeter of the frame = 53 inches

The width of the inside of the picture frame = 4•x

The height of the inside of the picture frame = 5•x

a. The equation for the outer perimeter of the picture frame is therefore;

2 × (4•x + 1 + 1) + 2 × (5•x + 1 + 1) = 53

Which gives;

2 × (4•x + 2) + 2 × (5•x + 2) = 53

8•x + 4 + 10•x + 4 = 53

A simplified equation for the outer perimeter of the picture frame is therefore;

  • 18•x + 8 = 53

b. Solving the above equation, we have;

18•x + 8 = 53

18•x = 53 - 8 = 45

18•x = 45

Therefore;

x = 45 ÷ 18 = 2.5

x = 2.5

The width and height of the picture frame are therefore;

Width = 4•x = 4 × 2.5 = 10

Height = 5•x = 5 × 2.5 = 12.5

Which gives;

Width = 10 inches

Height = 12.5 inches

The enlargement factor, sf, is given by the ratio of a side of the picture frame to a side of the picture as follows;

sf = 12.5/5 = 2.5

  • The factor by which to enlarge the picture frame is 2.5

Learn more about linear scale factors here:

brainly.com/question/19381630

#SPJ1

3 0
2 years ago
Find the slope of the line passing through the<br> points<br> (-9, 2) and (7, 2).
Alisiya [41]

Answer:

0

Step-by-step explanation:

-y₁ + y₂\-x₁ + x₂ = m

\frac{ - 2 + 2}{9 + 7}  =  \frac{0}{16}  = 0

I am joyous to assist you anytime.

3 0
3 years ago
Help me with this ASAP plz!!
evablogger [386]

Answer:

Rate of change = 2 & Initial value = -1

7 0
2 years ago
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