Question

The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 122m, 22m and 120m. The advertisements yield an earning of rupees 5000 per m^2 per year. A company hired one of its walls for 3 months. How much rent did it pay?

Answer 1

Answer:

1499750 rupees

Step-by-step explanation:

Let's find the area of the triangle first

S= (122+20+120)/2

S = 131

Area = √(131(131-122)(131-20)(131-120))

Area=√( 131(9)(111)(11))

Area= √(1439559)

Area= 1199.8 m²

5000 rupees per m² per year

So in a year it will earn

5000 = 1 m²

1199.8m² = 5000*1199.8

= 5999000 rupees for the year

In three months it will earn

5999000*(3/12)

= 5999000(0.25)

= 1499750 rupees