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2 years ago

A picture shows the net of the lateral surface of the cone. Which statement about this cone is NOT true?

Mathematics

2 answers:

Archy [21]2 years ago

7 0

Answer:

The area of the net is not π • 9^2

:P no explanation for u

const2013 [10]2 years ago

7 0

Answer:

The are of the net is pi times 9 squared is incorrect. (D)

Step-by-step explanation:

It doesn't make sense.

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27- 2b greater or equal to - 6

dezoksy [38]

27-2b > -6
-2b > -6-27
-2b > -33
b < -33/-2 (you have to change the sign when you divide with a negative number)
b < 16.5
(all the signs are supposed to have a line under them to make them greater or equal or less than or equal to)

5 0

2 years ago

Factor out<br> the GCF<br> 56x^2? + 16x + 64

ycow [4]

I’m not 100% sure but I think it’s 4 for the gcf

4 0

2 years ago

Triangle ABC is shown below.

Andrew [12]

Answer:

C.) 14

Step-by-step explanation:

Look at the triangle: angles b and c have the same arch, so they are congruent.

In a triangle, if two angles are congruent, then the triangle is isosceles, having two equal sides.

The sides opposite the congruent angles are congruent:

∠B → opposite side → AC

∠C → opposite side → AB

The sides AB and AC are equal. Make an equation:

$AB=AC\\\\2x=3x-7$

Simplify the equation, solving for x. Add 7 to both sides:

$2x+7=3x-7+7\\\\2x+7=3x$

Subtract 2x from both sides:

$2x-2x+7=3x-2x\\\\7=x$

The value of x is 7. Insert the value of x into the given length of AC:

$AC=3(7)-7$

Simplify multiplication:

$AC=21-7$

Subtract:

$AC=14$

Therefore, the length of the line segment AC is 14.

:Done

8 0

2 years ago

given examples of relations that have the following properties 1) relexive in some set A and symmetric but not transitive 2) equ

rodikova [14]

Answer: 1) R = {(a, a), (а,b), (b, a), (b, b), (с, с), (b, с), (с, b)}.

It is clearly not transitive since (a, b) ∈ R and (b, c) ∈ R whilst (a, c) ¢ R. On the other hand, it is reflexive since (x, x) ∈ R for all cases of x: x = a, x = b, and x = c. Likewise, it is symmetric since (а, b) ∈ R and (b, а) ∈ R and (b, с) ∈ R and (c, b) ∈ R.

2) Let S=Z and define R = {(x,y) |x and y have the same parity}

i.e., x and y are either both even or both odd.

The parity relation is an equivalence relation.

a. For any x ∈ Z, x has the same parity as itself, so (x,x) ∈ R.

b. If (x,y) ∈ R, x and y have the same parity, so (y,x) ∈ R.

c. If (x.y) ∈ R, and (y,z) ∈ R, then x and z have the same parity as y, so they have the same parity as each other (if y is odd, both x and z are odd; if y is even, both x and z are even), thus (x,z)∈ R.

3) A reflexive relation is a serial relation but the converse is not true. So, for number 3, a relation that is reflexive but not transitive would also be serial but not transitive, so the relation provided in (1) satisfies this condition.

Step-by-step explanation:

1) By definition,

a) R, a relation in a set X, is reflexive if and only if ∀x∈X, xRx ---> xRx.

That is, x works at the same place of x.

b) R is symmetric if and only if ∀x,y ∈ X, xRy ---> yRx

That is if x works at the same place y, then y works at the same place for x.

c) R is transitive if and only if ∀x,y,z ∈ X, xRy∧yRz ---> xRz

That is, if x works at the same place for y and y works at the same place for z, then x works at the same place for z.

2) An equivalence relation on a set S, is a relation on S which is reflexive, symmetric and transitive.

3) A reflexive relation is a serial relation but the converse is not true. So, for number 3, a relation that is reflexive but not transitive would also be serial and not transitive.

QED!

6 0

2 years ago

What is the length of XQY?

yulyashka [42]

Answer:

Step-by-step explanation:

First you must find the circumference of the entire circle and to do this you use 2πr. The radius in this case is PX=15. This means that the circumference is 30π. Now to find the arc length, we know that the measure of arc XY is 23 degrees, and since there are 360 total degrees in a circle, we must subtract 23 from 360 to get 337° as the measure of arc XQY. Now we have to find what portion of the circumference of the circle is in this arc, and to do this you divide the arc length (337°) by 360° and multiply by the circumference of the circle. Doing this would get you $\frac{337}{360} *30\pi$ which equals ~28. Finally, you have to multiply this by the value of pi and get approximately 88, which is your answer.

3 0

3 years ago

Read 2 more answers