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Vaselesa [24]
3 years ago
12

3/4 is added to x, the result is 9/8. What is the value of x?

Mathematics
1 answer:
KIM [24]3 years ago
4 0

Answer:

x=3/8

Step-by-step explanation:

turn 3/4 into a fraction that has a denominator of 8 3/4x2= 6/8

To get it to 9/8 you add x which is 3/8

so 3/8+6/8 is 9/8

x=3/8

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The value of x and MN if N is between M and P, MP=60, MN=6x-7, and NP=2x+3
Sergio039 [100]
MN + NP = MP
6x - 7 + 2x + 3 = 60
8x - 4 = 60
8x = 64
x = 8

MN = 6(8) - 7 = 56 - 7 = 49

answer
x = 8
MN = 49
5 0
3 years ago
Find the distance between each pair of points<br> 8) (2, 6), (5, 10)<br> 9) (-3,-10), (-3,5)
Lapatulllka [165]

Answer:

8) answer=5 9)answer=15

Step-by-step explanation:

all you have to do is replace in the following formula

\sqrt{(x2-x1)^{2}+ (y2-y1)^{2}} =d

Where

X1: is the first number of the first point

Y1: is the second number of the first point

X2:  is the first number of the second point

Y2: is the second number of the second point

you replace in the formula and solve

I attach solution

4 0
3 years ago
What is the diameter of the circle? <br> Enter your answer in the box. <br> _____units
wel

Answer:

8 units because the diameter is the side to side length of the circle so when you count it you get 8 units.

5 0
2 years ago
If a pool is 4 m wide and 16 m diagonally across, how long is the pool? (Pyth. Theorem)
alukav5142 [94]

Answer:

L=4\sqrt{15}\ m

or

L=15.49\ m

Step-by-step explanation:

we know that

Applying the Pythagorean Theorem in the rectangular pool

d^2=L^2+W^2

where

d is the diagonal of the pool

L is the length of the pool

W is the wide of the pool

we have

d=16\ m\\W=4\ m

substitute the given values

16^2=L^2+4^2

solve for L

L^2=16^2-4^2\\L^2=240\\L=\sqrt{240}\ m

simplify

L=4\sqrt{15}\ m

or

L=15.49\ m

4 0
3 years ago
Her the
Otrada [13]

Answer:

13. m∠MN + m∠NMP = m∠MP.

14. m∠NMP - m∠OMP = m∠NMO.

~

15. x = 3 + y and -2y + 3 < -1 : Given

16. x > y : x = 3 + y

17. -2y < -4 : -2y < -4

18. y > 2 : y > 2

19. x > 2 : x = 3 + y and y > 2

<u>------------------------------------------</u>

5 0
2 years ago
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