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Vaselesa [24]
3 years ago
12

3/4 is added to x, the result is 9/8. What is the value of x?

Mathematics
1 answer:
KIM [24]3 years ago
4 0

Answer:

x=3/8

Step-by-step explanation:

turn 3/4 into a fraction that has a denominator of 8 3/4x2= 6/8

To get it to 9/8 you add x which is 3/8

so 3/8+6/8 is 9/8

x=3/8

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1. \:  =  > 4( - 7) \\  = 4 \times  - 7 \\  =  - 28

3. \:  =  > 9( - 12) \\  = 9 \times  - 12 \\  =  - 108

4. \:  =  >  - 6( - 8.75) \\  = 6 \times 8.75 \\  = 52.5

5. =  > 27( - 3) \\  = 27 \times  - 3 \\  =  - 81

7. \:  =  >  - 55(0) \\  - 55 \times 0 \\  = 0

8. \:  =  > ( - 7)( - 7.25) \\  = 7 \times 7.25 \\  = 50.75

11. \:  =  > ( - 1) {}^{4}  \\  = 1 {}^{4}  \\  = 1

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3 years ago
If 3x+2y=12 and -4x+6y=24 what is the value of -x+2y
oksano4ka [1.4K]
(1) 3x+2y=12
(2) -4x+6y=24

Solving the system of equations using the method of substitution:
Isolating y in the first equation:
(1) 3x+2y=12→3x+2y-3x=12-3x→2y=12-3x→2y/2=(12-3x)/2→y=(12-3x)/2

Replacing "y" by (12-3x)/2 in the second equation:
(2) -4x+6y=24
y=(12-3x)/2→-4x+6[(12-3x)/2]=24

Solving for x:
-4x+3(12-3x)=24
-4x+36-9x=24
-13x+36=24
-13x+36-36=24-36
-13x=-12
-13x/(-13)=-12/(-13)
x=12/13

Replacing "x" by 12/13 in y=(12-3x)/2
x=12/13→y=[12-3(12/13)]/2
y=(12-36/13)/2
y={[(13)(12)-36]/13}/2
y=[(156-36)/13]/2
y=(120/13)/2
y=(120/13)(1/2)
y=60/13

x=12/13; y=60/13
-x+2y=-12/13+2(60/13)
-x+2y=-12/13+120/13
-x+2y=(-12+120)/13
-x+2y=108/13

Answer: The value of -x+2y is 108/13 
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3 years ago
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