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ankoles [38]
2 years ago
12

Solve the following equation. Then place the correct number in the box provided.

Mathematics
1 answer:
mylen [45]2 years ago
7 0

Answer:

x=3

Step-by-step explanation:

1. Add the numbers on both sides of the equation to get 9 (7+2) and 12 (9+3).

9+x=12

2. Subtract the 9 from 12 to get the x by itself.

x=3

and you get your answer.

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Ok can someone help me thanks!!
kotegsom [21]

Answer:

A constant of $20 can be multiplied by the number of months to find the amount in the account.

Step-by-step explanation:

4×20=80

7×20=140

7 0
3 years ago
Read 2 more answers
What is the variance for 34, 46, 52, 29, 41, 38, 36, and 28
horsena [70]

Answer:

38

Step-by-step explanation:

add all the numbers and divide that number by the amount of numbers there.

34+46+52+29+41+38+36+28 / 8 = 304/8 = 38

8 0
3 years ago
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The body temperatures of a group of healthy adults have a bell-shaped distribution with a mean of 98.35°F and a standard deviati
DochEvi [55]

Answer:

a) 99.97%

b) 65%

Step-by-step explanation:

• 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ.

• 95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ.

• 99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ.

Mean of 98.35°F and a standard deviation of 0.64°F.

a. What is the approximate percentage of healthy adults with body temperatures within 3 standard deviations of the mean, or between 96.43°F and 100.27°F?

μ - 3σ

98.35 - 3(0.64)

= 96.43°F

μ + 3σ.

98.35 + 3(0.64)

= 100.27°F

The approximate percentage of healthy adults with body temperatures is 99.97%

b. What is the approximate percentage of healthy adults with body temperatures between 97 .71°F and 98.99°F?

within 1 standard deviation from the mean - that means between μ - σ and μ + σ.

μ - σ

98.35 - (0.64)

= 97.71°F

μ + σ.

98.35 + (0.64)

= 98.99°F

Therefore, the approximate percentage of healthy adults with body temperatures between 97.71°F and 98.99°F is 65%

4 0
3 years ago
The low temperature on Monday was 16°F. On Tuesday, the low was 18°F cooler. On Wednesday, the low temperature was –4 times Tues
drek231 [11]

Answer:

-4(16-18), [16 + (-18)](-4)

Step-by-step explanation:

Given: The low temperature on Monday was 16°F. The low temperature on Tuesday was 18°F cooler. The low temperature on Wednesday was –4 times Tuesday’s temperature.

To find: expression that can be used to describe the low temperature on Wednesday

Solution:

Temperature on Monday = 16°F

So,

Temperature on Tuesday = (16-18)\°F

Temperature on Wednesday = -4(16-18)\°F

So, expression -4(16-18)=(16-18)(-4) can be used to describe the low temperature on Wednesday.

Also,

(16-18)(-4)=[16 + (-18)](-4)\,\,\left \{\because  (a-b)=\left [ a+(-b) \right ] \right \}

So, expression [16 + (-18)](-4) also represent temperature on Wednesday.

3 0
3 years ago
Read 2 more answers
Michael is using a number line to evaluate the expression –8 – 3.
Yanka [14]

Answer:

Step-by-step explanation:

Michael is using a number line to evaluate the expression -8 - 3. After locating -8 on the number line , Michael could rewrite the expression as -8 + -3 and move 3 spaces to the left.

6 0
3 years ago
Read 2 more answers
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