Answer:

Step-by-step explanation:
Given
--- male committing a crime in an episode
-- Number of episodes
Required
Determine the probability of male committing a crime at least 3 times
This question illustrates binomial distribution and will be solved using;

So, the required probability is represented as:

And will be calculated using:














So:



Correct option C) 0.98%
<u>Step-by-step explanation:</u>
We know that , there are 2 black ace cards out of 52 cards in a deck & 13 hearts out of 52 cards . Here we have to tell What is the probability of drawing a black ace followed by a heart out of a deck when the cards aren't replaced . Let's find out:
Firstly , a black ace is drawn , so probability :
⇒ 
Now , A heart is drawn out of 51 cards ( as one black ace is already drawn !):
⇒ 
So , Probability of occurring both events is :
⇒ 
⇒ 
⇒ 
Percentage =
%
Therefore , Correct option C) 0.98%
Answer:

Step-by-step explanation:

Adding 2a to both sides

Taking sqrt on both sides

this is your answer, i hope this helps you
None of these are choices, because in order to make 20ths equal a 45th, it was to end in a 20,40,60,80, or ending in 00.