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lbvjy [14]
3 years ago
13

You have two pairs of sneakers. One pair of sneakers is currently worth $80 and its value increases by $5 per month. The other p

air of sneakers is currently worth $140 and its value decreases by $5 per month. Let m be the number of months. To find out how many months later will both sneakers have the same value, which of the following equations setup is correct?
Mathematics
1 answer:
mafiozo [28]3 years ago
3 0

Answer:

I don't know but here's an example.

Step-by-step explanation:

Here's a word problem to start with.

Jane spent $42 for shoes. This was $14 less than twice what she spent for a blouse. How much was the blouse?

First, identify what the question is asking for.

Jane spent $42 for shoes. This was $14 less than twice what she spent for a blouse . How much was the blouse?

Next, identify the numbers.

Jane spent $42 for shoes. This was $14 less than twice what she spent for a blouse . How much was the blouse?

Next, identify the key words. These include add, subtract, remove, spend, earn, less, more, times, twice, half, etc.

Jane spent $42 for shoes. This was $14 less than twice what she spent for a blouse . How much was the blouse?

Finally, convert everything into an equation.

42

=

2

⋅

blouse

−

14

Now, solve the equation.

56

=

2

⋅

b

l

o

u

s

e

b

l

o

u

s

e

=

28

The blouse was 28 dollars.

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Nikitich [7]

Solution for x+4=10 equation:
1x + 4 = 10
1x = 10 - 4
1x = 6 (divide both sides by 1 to get x)
1x/1 = 6/1
x = 6

I hope this helped.


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3 years ago
A monster pupcake is supposed to bake for 35 minutes.If luna said to take it out of the oven at 3:20 when did she put them in?
kolezko [41]

Answer:

she put them in at 2:45

Step-by-step explanation:

because 35 minutes before 3:20 is 2:45

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3 years ago
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Can anyone help me with this?<br><br> Reduce the fraction
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\bf \cfrac{-20t^5u^2v^3}{48t^7u^4v}\implies \cfrac{-20}{48}\cdot \cfrac{t^5u^2v^3}{t^7u^4v^1}\implies \cfrac{-5}{12}\cdot \cfrac{v^3v^{-1}}{t^7t^{-5}u^4u^{-2}}\implies \cfrac{-5}{12}\cdot \cfrac{v^{3-1}}{t^{7-5}u^{4-2}} \\\\\\ \cfrac{-5}{12}\cdot \cfrac{v^2}{t^2u^2}\implies \cfrac{-5v^2}{12t^2 u^2}

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Review the table showing wind speed, y, in miles per hour, measured x hours after midnight.
hodyreva [135]

The trigonometric function that best models the data is determined as y = 1.87sin(–0.29x + 4.79) + 6.13.

<h3>Trigonometric function that models the data</h3>

The trigonometric function that best models the data is determined as follows;

y = 1.87sin(-0.29x + 4.79) + 6.13

Use the above equation to check if its gives you values in the table;

<h3>when x = 1</h3>

y = 1.87sin(-0.29 x 1  + 4.79) + 6.13

y = 1.87sin(4.5 rad) + 6.13

y = 4.3

<h3>when x = 2</h3>

y = 1.87sin(-0.29 x 2  + 4.79) + 6.13

y = 1.87sin(4.21 rad) + 6.13

y = 4.49

<h3>when x = 4</h3>

y = 1.87sin(-0.29 x 4  + 4.79) + 6.13

y = 1.87sin(3.63 rad) + 6.13

y = 5.2

<h3>when x = 7</h3>

y = 1.87sin(-0.29 x 7  + 4.79) + 6.13

y = 1.87sin(2.76 rad) + 6.13

y = 6.8

<h3>when x = 9</h3>

y = 1.87sin(-0.29 x 9  + 4.79) + 6.13

y = 1.87sin(2.18 rad) + 6.13

y =7.7

<h3>when x = 10</h3>

y = 1.87sin(-0.29 x 10  + 4.79) + 6.13

y = 1.87sin(1.89 rad) + 6.13

y = 7.9

<h3>when x = 13</h3>

y = 1.87sin(-0.29 x 13  + 4.79) + 6.13

y = 1.87sin(1.02 rad) + 6.13

y = 7.72

<h3>when x = 17</h3>

y = 1.87sin(-0.29 x 17  + 4.79) + 6.13

y = 1.87sin(-0.14 rad) + 6.13

y = 5.9

<h3>when x = 20</h3>

y = 1.87sin(-0.29 x 20  + 4.79) + 6.13

y = 1.87sin(-1.01 rad) + 6.13

y = 4.6

Thus, the trigonometric function that best models the data is determined as y = 1.87sin(–0.29x + 4.79) + 6.13.

Learn more about trigonometry functions here: brainly.com/question/1143565

#SPJ1

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GalinKa [24]

Answer:

infinitely many solutions

Step-by-step explanation:

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