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balandron [24]
3 years ago
11

A cell has 5% salt concentration. It is placed into a solution with a 0.5% salt concentration. What will happen to the cell

Biology
1 answer:
yaroslaw [1]3 years ago
6 0

Answer:

The cell will shrink due to osmosis.

Explanation:

As in given question the salt concentration are much more inside the cell, than outside. In order to maintain equilibrium. the water inside the cell will start flowing outside in order to maintain equilibrium, causing shrinkage of cell. The ability of a cell to divide or function will reduce because of water loss. This phenomenon is seen in case of hypertonic solution. Water will start diffusing from the higher concentration to the lower concentration.

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How much 3M NaOH (MW=40) can be made from 10.0mL of a 10M solution?
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Explanation:

The given data is as follows.

              M_{1} = 3 M,           V_{1} = ?

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Therefore, calculate the volume of given solution as follows.

              M_{1} \times V_{1} = M_{2} \times V_{2}

Now, putting the given values into the above formula as follows.

            M_{1} \times V_{1} = M_{2} \times V_{2}

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or,                             = 0.033 L        (as 1 ml = 0.001 L)

Since, molarity of NaOH is given as 3 M and its volume is calculated as 33.3 ml.

           Molarity = \frac{\text{mass of solute}}{\text{molar mass of solute}} \times \frac{1}{\text{volume in L}}

               3 M = \frac{mass}{40 g/mol \times 0.033 L}

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Explanation:

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