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3 years ago

A wall is 20 feet long and requires 1,470 bricks to build. How high is the wall?

Mathematics

1 answer:

Arte-miy333 [17]3 years ago

3 0

Answer: The height of wall is 10.5 feet.

Step-by-step explanation:

Since we have given that

Number of bricks to build = 1470

Length of wall = 20 feet

We need to find the height of wall.

As we know that

Bricklayer's formula is given by

$N=7LH\\\\1470=7\times 20\times H\\\\1470=140\times H\\\\\dfrac{1470}{140}=H\\\\10.5\ ft=H$

Hence, the height of wall is 10.5 feet.

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Molly tried to evaluate 93\times5193×5193, times, 51 using partial products. Her work is shown below.

Mrac [35]

Since molly's solution tally's with the given solution, hence <em>Molly's solution is correct.</em>

Given the working on a partial product of 93 and 51 carried out by Molly as shown:

$\begin{array}{llrr} &&93 \\ &&\underline{{}\times51} \\ &\blueD{\text{Step 1}}&\blueD{3}& \blueD{1\times3\text{ ones}}\\ &\greenD{\text{Step 2}}&\greenD{90}& \greenD{1\times 9\text{ tens}}\\ &\maroonD{\text{Step 3}}&\maroonD{150}& \maroonD{50\times 3\text{ ones}}\\ &\goldE{\text{Step 4}}&\underline{{}+\goldE{ 4{,}500}}& \goldE{50\times 9\text{ tens}}\\ &\purpleD{\text{Step 5}}&\purpleD{4{,}743}& \end{array}$

This partial product can also be solved as shown below:

$93 \times 51 = (90+3)\times (50+1)$

Applying the distributive law:

$93 \times 51 = 90(50) + 90(1) + 3(50) + 3(1)\\93 \times 51 =4500 + 90 + 150 + 3\\93 \times 51 =4500+240+3\\93 \times 51 =4740+3\\93 \times 51 =4743$

Since molly's solution tally's with the given solution, hence <em>Molly solution is correct.</em>

Learn more about partial product at: brainly.com/question/24716925

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