Answer:
The greater the sample size the better is the estimation. A large sample leads to a more accurate result.
Step-by-step explanation:
Consider the table representing the number of heads and tails for all the number of tosses:
Number of tosses    n (HEADS)        n (TAILS)            Ratio
             10                         3                      7                    3 : 7 
            30                         14                    16                   7 : 8
           100                        60                   40                  3 : 2
Compute probability of heads for the tosses as follows:
         
The probability of heads in case of 10 tosses of a coin is -0.20 away from 50/50.
         
The probability of heads in case of 30 tosses of a coin is -0.033 away from 50/50.
         
The probability of heads in case of 100 tosses of a coin is 0.10 away from 50/50.
As it can be seen from the above explanation, that as the sample size is increasing the distance between the expected and observed proportion is decreasing.
This happens because, the greater the sample size the better is the estimation. A large sample leads to a more accurate result.
 
        
             
        
        
        
Answer:
= 486 in²
Step-by-step explanation:
Linear scale factor = Image distance/object distance
Therefore; Linear scale factor = OL'/OL
                                                  = 54/ 12 
                                                  = 9/2 
Area scale factor is equivalent to the square of linear scale factor
Thus;
Area scale factor = (9/2)² 
                              = 81/4
Hence; 81/4 = Area of larger rectangle/Area of smaller rectangle
Area of the smaller rectangle = 4 ×6 = 24 in²
Therefore; 
Area of enlarged or larger pic = 81/4× 24
                                                   <u>= 486 in²</u>
 
        
                    
             
        
        
        
Exponential decay is a very common process especially when we are talking about radioactive materials. So, there is already a common formula for this type of behavior which is written below:
A = Pe^-rt
where
A is the amount left after time t
P is the initial amount at t=0
r is the rate
Substituting the values,
A = (780 g)(e^-0.163*16)
A = 57.5 g
        
             
        
        
        
Answer:
Step-by-step explanation:
Check attachment for solution 
 
        
             
        
        
        
2abc - 3ab ║ 2 (2) (3) (4) - 3 (2) (3)
You would multiply and the products - you are going to subtract
2 × 2 × 3 × 4 = 48
3 × 2 × 3 =     - 18
                    -------
        answer:    30