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Olegator [25]
3 years ago
14

What 1/4(3.14)(5.4^3)(12)and any player boys out thereplzzzzzz im bored

Mathematics
2 answers:
Soloha48 [4]3 years ago
6 0

Answer is 1483.31088

Explanation:

It is asked that =(\frac{1}{4})(3.14)(5.4^{3} )(12)\\=(3.14)(5.4^{2} )(3)\\\\=(3.14)(157.464)(3)\\=1483.31088\\

Answer is 1483.31088

zhuklara [117]3 years ago
5 0

Answer: The answer is 1483.31088

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The sum of two numbers is 8. Is it possible for the difference of the two numbers to also be 8? Why or why not
r-ruslan [8.4K]

Answer: yes

Step-by-step explanation: because you would get the same number cause anything plus or even divided by 0  then 8 each time you try ex: 8 + 0 = 8

8 - 0 = 8

brainliest plz

4 0
3 years ago
Solve using the Quadratic Formula.<br><br> 3x2 + 2x + 1 = 0
Crazy boy [7]

Answer:

Hi! The correct answer is x= -7/2

Step-by-step explanation:

Solve the rational equation by combining expressions and isolating the variable x.

8 0
3 years ago
HELP!!<br>Find the third term of (x^2+3y)^3
lana66690 [7]

Answer:

T_{3}=27{x}^{2}y^2

Step-by-step explanation:

The given binomial expression is:

( {x}^{2} + 3y)^{3}

When we compare to:

{(a +b)}^{n}

We have

a =  {x}^{2}

b = 3y \\ n = 3

The nth term is given by;

T_{r+1}=^nC_ra^{n-r}b^r

To find the 3rd term, we put:

r + 1 = 3 \\ r = 2

We substitute into the formula to get:

T_{3}=^3C_2( {x}^{2} )^{3-2}(3y)^2

We simply:

T_{3}=3( {x}^{2} )^{1} \times 9y^2

T_{3}=27{x}^{2}y^2

3 0
3 years ago
The equations f(x)=-2x+3
hjlf

Answer:13

Step-by-step explanation:

4 0
3 years ago
Suppose you are bending stainless steel wire to make the earring shown below. The
lakkis [162]

Given parameters:

Length of earring hook  = 1.5cm

Length of given wire = 45cm

Dimension of the triangle = 3.2cm, 3.2cm and 2.1cm

Unknown:

Number of earrings that can be made from the wire = ?

To solve this problem, we need to calculate the total length of the earring we want to make.

  Total earring length  = Perimeter of earring + length of earring hook

                                      = 3.2 + 3.2 + 2.1 + 1.5  

                                      = 10cm

Now the length of the wire is 45cm,

  Number of earrings  = \frac{45}{10}  = 4.5 earrings

  But this is not reasonable, therefore, we can only forge 4 complete earrings from the given length with 5cm of wire remaining.

The number of earrings that can be made is 4.

4 0
3 years ago
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